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Statistics and Probability - Calculating Probability of Events

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Probability Scale: Probability is the numerical measure of the likelihood that an event will occur, ranging from 00 to 11. Visualize this as a horizontal line where 00 (on the far left) represents an impossible event, 0.50.5 (in the middle) represents an even chance, and 11 (on the far right) represents a certain event. All probabilities are expressed as fractions, decimals, or percentages within this range.

Sample Space (SS): The sample space is the set of all possible outcomes of an experiment. It can be visualized as a list within curly brackets, such as S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\} for a fair die, or as a grid where the x-axis and y-axis represent two different trials (like rolling two dice) to show every possible coordinate combination.

Theoretical vs. Experimental Probability: Theoretical probability is based on reasoning and mathematical calculation of what 'should' happen. Experimental probability (or relative frequency) is based on actual data from trials. You can visualize experimental probability using a frequency table that records the number of times an outcome occurs divided by the total number of trials conducted.

Complementary Events: The complement of event AA, denoted as AA', consists of all outcomes in the sample space that are NOT in AA. In a Venn diagram, if event AA is a circle inside a rectangular box (the sample space), AA' is the entire shaded area outside that circle but inside the box. The sum of the probability of an event and its complement is always 11.

Tree Diagrams: A visual tool used to calculate probabilities for multiple events occurring in sequence. Each stage of the experiment is represented by a set of 'branches'. You multiply probabilities along the branches to find the probability of a specific path (e.g., flipping a Head then a Tail) and ensure the sum of probabilities at any set of branches equals 11.

Venn Diagrams and Two-Way Tables: These are used to represent the relationship between two or more events. In a Venn diagram, the overlapping section (the intersection) represents outcomes where both events occur (ABA \cap B), while the area covered by both circles (the union) represents outcomes where either or both events occur (ABA \cup B). Two-way tables organize this same data into rows and columns for easy summation.

Mutually Exclusive Events: Events that cannot happen at the same time. Visually, in a Venn diagram, mutually exclusive events are represented by two circles that do not overlap or touch. If events are mutually exclusive, the probability of either occurring is simply the sum of their individual probabilities.

📐Formulae

P(E)=Number of favorable outcomesTotal number of possible outcomesP(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}

P(A)=1P(A)P(A') = 1 - P(A)

Relative Frequency=Frequency of eventTotal number of trials\text{Relative Frequency} = \frac{\text{Frequency of event}}{\text{Total number of trials}}

P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B)

Expected Outcomes=P(E)×n (where n is the number of trials)\text{Expected Outcomes} = P(E) \times n \text{ (where } n \text{ is the number of trials)}

💡Examples

Problem 1:

A bag contains 55 red marbles, 33 blue marbles, and 22 green marbles. If one marble is picked at random, what is the probability that it is NOT blue?

Solution:

  1. Find the total number of marbles: 5+3+2=105 + 3 + 2 = 10.
  2. Identify the number of blue marbles: n(blue)=3n(\text{blue}) = 3.
  3. Calculate the probability of picking a blue marble: P(blue)=310=0.3P(\text{blue}) = \frac{3}{10} = 0.3.
  4. Use the complement rule to find the probability of NOT blue: P(blue)=1P(blue)P(\text{blue}') = 1 - P(\text{blue}).
  5. P(blue)=10.3=0.7P(\text{blue}') = 1 - 0.3 = 0.7.

Explanation:

To find the probability of the complement (not blue), we first determine the total sample space and the probability of the event occurring, then subtract that from 11.

Problem 2:

A fair six-sided die is rolled and a fair coin is tossed. Use a tree diagram approach to find the probability of rolling a number greater than 44 and flipping a 'Heads'.

Solution:

  1. Probability of rolling a number greater than 44 (outcomes are 55 and 66): P(>4)=26=13P(>4) = \frac{2}{6} = \frac{1}{3}.
  2. Probability of flipping Heads: P(H)=12P(H) = \frac{1}{2}.
  3. Since these are independent events, multiply the probabilities along the branches of the mental tree diagram: P(>4 and H)=P(>4)×P(H)P(>4 \text{ and } H) = P(>4) \times P(H).
  4. Calculation: 13×12=16\frac{1}{3} \times \frac{1}{2} = \frac{1}{6}.

Explanation:

This problem treats the die roll and coin toss as independent events. We calculate the probability of each separate event and then multiply them to find the probability of both occurring together.