krit.club logo

Number - Square Roots and Cube Roots

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Square Roots and Area: The square root of a number nn, written as n\sqrt{n}, represents the side length of a square whose area is exactly nn units squared. Visually, if you have a square grid containing 1616 small squares, the length of one side is 16=4\sqrt{16} = 4 units.

Perfect Squares: These are integers that are the result of squaring another integer. Common examples include 1,4,9,16,25,36,49,64,81,1, 4, 9, 16, 25, 36, 49, 64, 81, and 100100. On a number line, perfect squares appear at increasing intervals as the base integer grows.

Cube Roots and Volume: The cube root of a number nn, denoted as n3\sqrt[3]{n}, is the edge length of a 3D cube with a volume of nn. For example, a rubik's cube made of 2727 smaller individual cubes has an edge length of 273=3\sqrt[3]{27} = 3 units.

Radical Notation: The symbol \sqrt{} is called a radical. The number inside is the radicand, and the small number above the checkmark is the index. If no index is shown, it is assumed to be a square root (index 22). For cube roots, the index is always 33.

Negative Radicands: A square root of a negative number (e.g., 16\sqrt{-16}) is not a real number because no real number multiplied by itself results in a negative value. However, cube roots of negative numbers are real; for example, 643=4\sqrt[3]{-64} = -4 because (4)×(4)×(4)=64(-4) \times (-4) \times (-4) = -64.

Estimation of Roots: For non-perfect squares like 10\sqrt{10}, we estimate the value by finding the two closest perfect squares. Since 9<10<16\sqrt{9} < \sqrt{10} < \sqrt{16}, we know that 3<10<43 < \sqrt{10} < 4. On a number line, 10\sqrt{10} would be positioned very close to 33.

Inverse Operations: Squaring a number and taking its square root are inverse operations. Similarly, cubing and taking a cube root are inverses. For example, 52=255^2 = 25 and 25=5\sqrt{25} = 5; 43=644^3 = 64 and 643=4\sqrt[3]{64} = 4.

📐Formulae

x2=x\sqrt{x^2} = |x|

(x)2=x(\sqrt{x})^2 = x (for x0x \ge 0)

x33=x\sqrt[3]{x^3} = x

a×b=a×b\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}

ab=ab\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}

a×b3=a3×b3\sqrt[3]{a \times b} = \sqrt[3]{a} \times \sqrt[3]{b}

💡Examples

Problem 1:

Evaluate the expression: 249+2732\sqrt{49} + \sqrt[3]{-27}

Solution:

Step 1: Find the square root of 4949. Since 7×7=497 \times 7 = 49, 49=7\sqrt{49} = 7. Step 2: Find the cube root of 27-27. Since (3)×(3)×(3)=27(-3) \times (-3) \times (-3) = -27, 273=3\sqrt[3]{-27} = -3. Step 3: Substitute the values back into the expression: 2(7)+(3)2(7) + (-3). Step 4: Perform the multiplication: 143=1114 - 3 = 11.

Explanation:

This problem requires evaluating a square root and a cube root separately before applying the order of operations (multiplication then addition).

Problem 2:

Find the value of xx if the area of a square is 144 cm2144 \text{ cm}^2 and its side length is x\sqrt{x}.

Solution:

Step 1: Identify the relationship between side length and area. Area =side×side=side2= \text{side} \times \text{side} = \text{side}^2. Step 2: We are given Area =144= 144, so side=144\text{side} = \sqrt{144}. Step 3: Calculate 144=12\sqrt{144} = 12. Step 4: The problem states the side length is also x\sqrt{x}, so x=12\sqrt{x} = 12. Step 5: Square both sides to solve for xx: (x)2=122(\sqrt{x})^2 = 12^2, which gives x=144x = 144.

Explanation:

This solution uses the geometric definition of a square root to link area to side length and then uses inverse operations to isolate xx.