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Number - Scientific Notation

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Scientific notation, also known as standard form, is a method used to write very large or very small numbers in a concise format. It is written as a×10na \times 10^n, where the coefficient aa must satisfy 1a<101 \le a < 10 and the exponent nn must be an integer. Visually, the coefficient aa always has exactly one non-zero digit to the left of the decimal point.

When converting a large number (greater than 10) to scientific notation, the decimal point is moved to the left. Each movement or 'jump' increases the value of the positive exponent nn. For example, to convert 5,800,0005,800,000, imagine the decimal point jumping 6 places from the end of the number to the position between 55 and 88, resulting in 5.8×1065.8 \times 10^6.

To convert a small number (between 0 and 1) to scientific notation, the decimal point moves to the right. Each jump to the right results in a negative exponent nn. If you have 0.000420.00042, visualize the decimal shifting 4 places to the right to sit between 44 and 22, which gives 4.2×1044.2 \times 10^{-4}.

When multiplying numbers in scientific notation, you multiply the coefficients (aa) and add the exponents (nn) according to the laws of indices. If the resulting coefficient is not between 1 and 10, you must adjust it. For example, (4×102)×(3×105)(4 \times 10^2) \times (3 \times 10^5) initially gives 12×10712 \times 10^7, but must be corrected to 1.2×1081.2 \times 10^8 by shifting the decimal left and increasing the exponent.

When dividing numbers in scientific notation, divide the coefficients and subtract the exponent of the divisor from the exponent of the dividend. This follows the index law xmxn=xmn\frac{x^m}{x^n} = x^{m-n}. For instance, (6×108)÷(2×103)(6 \times 10^8) \div (2 \times 10^3) results in 3×1053 \times 10^5.

Addition and subtraction require the exponents of the powers of 10 to be the same before the operation can be performed. Visualize this as aligning the place values. If the exponents differ, you must rewrite one of the numbers. For example, to add 2×1032 \times 10^3 and 3×1023 \times 10^2, you could change 3×1023 \times 10^2 to 0.3×1030.3 \times 10^3 so that you can add the coefficients: (2+0.3)×103=2.3×103(2 + 0.3) \times 10^3 = 2.3 \times 10^3.

To convert from scientific notation back to ordinary (standard) decimal form, look at the exponent nn. If nn is positive, move the decimal point nn places to the right (filling gaps with zeros). If nn is negative, move the decimal point nn places to the left, which visually makes the number smaller and closer to zero.

📐Formulae

a×10na \times 10^n where 1a<101 \le a < 10 and nZn \in \mathbb{Z}

(a×10m)×(b×10n)=(a×b)×10m+n(a \times 10^m) \times (b \times 10^n) = (a \times b) \times 10^{m+n}

(a×10m)÷(b×10n)=(a÷b)×10mn(a \times 10^m) \div (b \times 10^n) = (a \div b) \times 10^{m-n}

a×100=a×1=aa \times 10^0 = a \times 1 = a

💡Examples

Problem 1:

Write the number 0.00008020.0000802 in scientific notation.

Solution:

Step 1: Identify the first non-zero digit, which is 88. Step 2: Move the decimal point to the right until it is placed immediately after the 88. Step 3: Count the jumps: the decimal moves 5 places to the right (0.00008.020.00008.02). Step 4: Because the decimal moved to the right, the exponent is negative, so n=5n = -5. Step 5: Combine the coefficient and the power: 8.02×1058.02 \times 10^{-5}.

Explanation:

The decimal is shifted 5 places to the right to create a coefficient 8.028.02, which is between 1 and 10. The negative exponent reflects that the original number was much smaller than 1.

Problem 2:

Evaluate (2.5×103)×(4×108)(2.5 \times 10^{-3}) \times (4 \times 10^8) and express the result in scientific notation.

Solution:

Step 1: Multiply the coefficients: 2.5×4=102.5 \times 4 = 10. Step 2: Add the exponents using index laws: (3)+8=5(-3) + 8 = 5. Step 3: Combine the results to get 10×10510 \times 10^5. Step 4: Adjust to correct scientific notation format. Since 1010 is not less than 10, move the decimal one place to the left to get 1.01.0 and increase the exponent by 1. Final result: 1×1061 \times 10^6.

Explanation:

We first apply the multiplication rules for scientific notation. Because the initial product of the coefficients resulted in 10, we had to re-normalize the expression to ensure the coefficient aa is in the range 1a<101 \le a < 10.