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Geometry and Measurement - Area of 2D Shapes (Trapeziums, Rhombuses, General Polygons)

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Understanding the Trapezium: A trapezium (also known as a trapezoid) is a quadrilateral with at least one pair of parallel sides, labeled as aa and bb. Visually, the perpendicular height hh is the vertical line segment that connects these two parallel bases at right angles (9090^{\circ}), and it is this vertical distance, not the length of the slanted sides, that is used to calculate area.

The Rhombus and its Diagonals: A rhombus is a special type of parallelogram where all four sides are of equal length. Its most unique visual feature is that its diagonals, d1d_1 and d2d_2, bisect each other at a perpendicular angle. This creates four congruent right-angled triangles inside the shape, leading to an area formula based on the product of these diagonals.

Rhombus as a Parallelogram: Since every rhombus is also a parallelogram, its area can also be visualized as a base bb and a perpendicular height hh. If you imagine 'straightening' the rhombus, the area is simply the product of any side and the vertical distance to the opposite side.

Decomposing General Polygons: Complex or irregular polygons can be solved by 'partitioning' them into simpler, non-overlapping shapes. Visually, this involves drawing auxiliary dotted lines inside the polygon to break it into recognizable rectangles, triangles, and trapeziums, then summing the individual areas.

The Subtraction Method: For some general polygons, it is more efficient to imagine the shape enclosed within a larger, simple bounding box (like a large rectangle). The area is found by calculating the area of this large rectangle and then subtracting the areas of the 'empty' shapes (usually right-angled triangles) in the corners that are not part of the polygon.

Perpendicular vs. Slant Height: A common pitfall in geometry is using a slanted side length for area calculations. For trapeziums and rhombuses, the height hh must always be the perpendicular distance. In diagrams, look for the small square symbol (9090^{\circ} indicator) to identify the correct height value.

Unit Consistency and Conversion: Area is always expressed in square units (mm2mm^2, cm2cm^2, m2m^2). Before applying formulas, ensure all side lengths and heights are converted to the same unit of measurement to avoid calculation errors.

📐Formulae

Area of a Trapezium: A=frac12(a+b)hA = \\frac{1}{2}(a + b)h

Area of a Rhombus (Diagonal Method): A=frac12timesd1timesd2A = \\frac{1}{2} \\times d_1 \\times d_2

Area of a Rhombus/Parallelogram (Base/Height Method): A=btimeshA = b \\times h

Area of General Polygons: Atotal=A1+A2+...+AnA_{total} = A_1 + A_2 + ... + A_n

💡Examples

Problem 1:

Calculate the area of a trapezium where the two parallel sides measure 14textcm14\\text{ cm} and 22textcm22\\text{ cm}, and the perpendicular distance between them is 9textcm9\\text{ cm}.

Solution:

  1. Identify the given dimensions: a=14textcma = 14\\text{ cm}, b=22textcmb = 22\\text{ cm}, and h=9textcmh = 9\\text{ cm}. \ 2. Write down the trapezium area formula: A=frac12(a+b)hA = \\frac{1}{2}(a + b)h. \ 3. Substitute the values into the formula: A=frac12(14+22)times9A = \\frac{1}{2}(14 + 22) \\times 9. \ 4. Add the bases inside the parentheses: A=frac12(36)times9A = \\frac{1}{2}(36) \\times 9. \ 5. Multiply: A=18times9=162A = 18 \\times 9 = 162.

Explanation:

To find the area, we sum the parallel bases, multiply by the perpendicular height, and then take half of that product. The final area is 162textcm2162\\text{ cm}^2.

Problem 2:

A rhombus has a side length of 5textcm5\\text{ cm} and its two diagonals measure 6textcm6\\text{ cm} and 8textcm8\\text{ cm}. Find the area of the rhombus.

Solution:

  1. Identify the relevant dimensions for the diagonal formula: d1=6textcmd_1 = 6\\text{ cm} and d2=8textcmd_2 = 8\\text{ cm} (the side length of 5textcm5\\text{ cm} is not needed for this formula). \ 2. State the formula: A=frac12timesd1timesd2A = \\frac{1}{2} \\times d_1 \\times d_2. \ 3. Substitute the values: A=frac12times6times8A = \\frac{1}{2} \\times 6 \\times 8. \ 4. Perform the multiplication: A=frac12times48A = \\frac{1}{2} \\times 48. \ 5. Final calculation: A=24A = 24.

Explanation:

Using the diagonal method is the most direct way to find the area here. Note that the side length was extra information provided to test your ability to choose the correct dimensions. The area is 24textcm224\\text{ cm}^2.