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Algebra - Factorization of Algebraic Expressions

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Factorization as the Reverse of Expansion: To factorize an algebraic expression means to write it as a product of its factors. If you imagine a large rectangle where the total area is the algebraic expression, factorizing is the process of finding the specific lengths of its sides. For example, ab+acab + ac represents the area, and a(b+c)a(b + c) represents the length and width.

Common Factor Extraction: This is the primary step where you identify the Highest Common Factor (HCF) of all terms in the expression and place it outside a bracket. Visually, this is like identifying a common width for multiple rectangular areas and 'pulling' it out to see the remaining lengths.

Difference of Two Squares (DOTS): This pattern occurs when a perfect square is subtracted from another, such as a2b2a^2 - b^2. Visually, if you take a large square of side aa and remove a smaller square of side bb from the corner, the remaining shape can be sliced and rearranged into a single rectangle with dimensions (a+b)(a+b) and (ab)(a-b).

Factorizing by Grouping: This technique is often used for expressions with four terms. You group the terms into two pairs and factor out the HCF from each pair. If the resulting binomials in the brackets are identical, they become a single common factor. Visually, this is like organizing four separate area blocks into two distinct rows that eventually align to form a single large grid.

Factoring Monic Quadratic Trinomials: For expressions like x2+bx+cx^2 + bx + c, you look for two integers that multiply to give cc (the product) and add to give bb (the sum). Visually, this is the challenge of taking one x2x^2 tile, bb number of xx tiles, and cc unit squares and arranging them into a perfectly solid rectangle without any gaps.

Perfect Square Trinomials: These are special trinomials that factor into a squared binomial, such as (a+b)2(a+b)^2 or (ab)2(a-b)^2. You can identify them because the first and last terms are perfect squares, and the middle term is exactly twice the product of the square roots of the outer terms. Visually, these pieces always form a perfect square rather than a non-square rectangle.

📐Formulae

ab+ac=a(b+c)ab + ac = a(b + c) (Highest Common Factor)

a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b) (Difference of Two Squares)

a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2 (Perfect Square Trinomial - Addition)

a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2 (Perfect Square Trinomial - Subtraction)

x2+(p+q)x+(p×q)=(x+p)(x+q)x^2 + (p+q)x + (p \times q) = (x+p)(x+q) (Quadratic Trinomials)

💡Examples

Problem 1:

Factorize completely: 4x2364x^2 - 36

Solution:

Step 1: Look for the Highest Common Factor (HCF). Both 4x24x^2 and 3636 are divisible by 44. \ 4(x29)4(x^2 - 9) \ Step 2: Recognize the expression inside the bracket. x29x^2 - 9 is a difference of two squares because x2=(x)2x^2 = (x)^2 and 9=(3)29 = (3)^2. \ Step 3: Apply the formula a2b2=(ab)(a+b)a^2 - b^2 = (a-b)(a+b) where a=xa=x and b=3b=3. \ Final Answer: 4(x3)(x+3)4(x - 3)(x + 3)

Explanation:

The solution first simplifies the expression by removing a common numerical factor, then applies the Difference of Two Squares identity to the remaining binomial.

Problem 2:

Factorize the trinomial: x25x14x^2 - 5x - 14

Solution:

Step 1: Identify the values for the sum (b=5b = -5) and the product (c=14c = -14). \ Step 2: Find two numbers that multiply to 14-14 and add to 5-5. \ Factors of 14-14 include: (14,1),(14,1),(7,2),(7,2)(-14, 1), (14, -1), (-7, 2), (7, -2). \ Step 3: Test the sums: 7+2=5-7 + 2 = -5. This matches our middle coefficient. \ Step 4: Write the factors in the form (x+p)(x+q)(x + p)(x + q). \ Final Answer: (x7)(x+2)(x - 7)(x + 2)

Explanation:

This approach uses the 'sum and product' method for monic quadratics. Since the product is negative, the two numbers must have opposite signs.