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Mensuration - Area of Polygons

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Definition of Area: Area is the measure of the region enclosed within the boundary of a closed plane figure. It is expressed in square units such as cm2cm^{2} or m2m^{2}. Visually, it represents the number of unit squares that can fit inside the shape.

Area of a Trapezium: A trapezium is a quadrilateral with exactly one pair of parallel sides. Visually, imagine a shape with a top horizontal line (aa) and a longer bottom horizontal line (bb), connected by two slanted side legs. The area is found by multiplying the average of the parallel sides by the perpendicular distance (hh) between them.

Area of a General Quadrilateral: Any irregular four-sided polygon can be divided into two triangles by drawing a diagonal (dd). Visually, if you draw a line from one corner to the opposite corner, you create two triangles. The area of the quadrilateral is the sum of the areas of these two triangles, calculated using the diagonal as a base and the heights (h1h_1 and h2h_2) dropped from the other two vertices.

Area of a Rhombus: A rhombus is a quadrilateral where all sides are equal. A unique property is that its diagonals (d1d_1 and d2d_2) intersect at right angles (9090^{\circ}) and bisect each other. Visually, it looks like a tilted square where the area is half the product of the lengths of these internal perpendicular diagonals.

Area of a Parallelogram: A parallelogram is a quadrilateral where opposite sides are parallel and equal. Visually, it resembles a rectangle that has been pushed to one side. Its area is determined by the length of its base (bb) and the vertical height (hh) perpendicular to that base.

Area of a General Polygon: Complex polygons (like pentagons or hexagons) can be measured by dividing them into simpler shapes such as triangles, rectangles, or trapezia. Visually, this is done by drawing internal diagonals or perpendicular lines to a central base line, effectively turning one large irregular shape into a 'puzzle' of smaller known shapes.

Relationship between Units: When calculating area, all dimensions must be in the same unit. Remember that 11 cm2=100cm^{2} = 100 mm2mm^{2} and 11 m2=10,000m^{2} = 10,000 cm2cm^{2}. In a visual context, 11 m2m^{2} is a square with side lengths of 100100 cmcm each.

📐Formulae

Area of a Trapezium = 12×(a+b)×h\frac{1}{2} \times (a + b) \times h

Area of a General Quadrilateral = 12×d×(h1+h2)\frac{1}{2} \times d \times (h_1 + h_2)

Area of a Rhombus = 12×d1×d2\frac{1}{2} \times d_1 \times d_2

Area of a Parallelogram = base×heightbase \times height

Area of a Triangle = 12×base×height\frac{1}{2} \times base \times height

Area of a Square = side×side=s2side \times side = s^{2}

Area of a Rectangle = length×breadthlength \times breadth

💡Examples

Problem 1:

Find the area of a trapezium whose parallel sides are 1515 cmcm and 2525 cmcm, and the perpendicular distance between them is 1010 cmcm.

Solution:

Given: Parallel side a=15a = 15 cmcm Parallel side b=25b = 25 cmcm Height h=10h = 10 cmcm

Using the formula: Area = 12×(a+b)×h\frac{1}{2} \times (a + b) \times h Area = 12×(15+25)×10\frac{1}{2} \times (15 + 25) \times 10 Area = 12×40×10\frac{1}{2} \times 40 \times 10 Area = 20×1020 \times 10 Area = 200200 cm2cm^{2}

Explanation:

First, identify the two parallel sides (bases) and the height. Substitute these values into the trapezium area formula and perform the arithmetic operations.

Problem 2:

The area of a rhombus is 240240 cm2cm^{2}. If one of its diagonals is 1616 cmcm, find the length of the other diagonal.

Solution:

Given: Area of rhombus = 240240 cm2cm^{2} Diagonal d1=16d_1 = 16 cmcm

Using the formula: Area = 12×d1×d2\frac{1}{2} \times d_1 \times d_2 240=12×16×d2240 = \frac{1}{2} \times 16 \times d_2 240=8×d2240 = 8 \times d_2 d2=2408d_2 = \frac{240}{8} d2=30d_2 = 30 cmcm

Explanation:

Apply the area formula for a rhombus. Since the area and one diagonal are known, rearrange the equation to solve for the unknown diagonal d2d_2 by dividing the area by half of the known diagonal.