Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Factorisation is the process of writing an algebraic expression as a product of two or more expressions. It is the reverse of the Distributive Law. Visualise this like taking a complex machine and dismantling it into its original component parts or 'factors'.
Factors of Monomials: A monomial can be broken down into its irreducible factors. For example, has factors and . These are called 'irreducible' because they cannot be factorised further, much like prime numbers in arithmetic.
Method of Common Factors: This involves identifying the Highest Common Factor (HCF) of all the terms in the expression. Think of this as looking at a row of boxes and picking out the exact same item that appears in every single box to place it outside.
The Distributive Property in Reverse: In multiplication, we use . In factorisation, we observe the common in and pull it out to get . This can be visualised as finding the common width 'a' for two adjacent rectangles with areas and .
Identifying Numerical HCF: For the numerical coefficients, find the largest number that divides all of them. For example, in , the HCF of and is . On a number line, this is the largest step size that lands exactly on both and .
Identifying Literal (Variable) HCF: For the variables, look for the lowest power of each common variable. In and , the common factor is because it is the largest power contained within both terms.
Irreducible Form: An expression is said to be in its factorised form when no further common factors can be extracted. Visually, this is represented as a product of brackets where the contents inside each bracket have no common factors remaining.
📐Formulae
💡Examples
Problem 1:
Factorise the expression:
Solution:
Step 1: Find the factors of each term. Step 2: Identify the common factors. The common factors are and . Step 3: Calculate the HCF. Step 4: Write the expression as product of HCF and the remaining terms.
Explanation:
We first break down both terms into their prime and variable factors. By circling the components that appear in both lists (), we determine the HCF. Dividing each original term by gives us the terms left inside the bracket.
Problem 2:
Factorise
Solution:
Step 1: Find the numerical HCF of the coefficients and . Factors of Factors of Factors of The common numerical factor is . Step 2: Check for literal (variable) common factors. There are no variables () common to all three terms. Step 3: Factor out the .
Explanation:
In this problem, there are no common variables across all terms. We only find the HCF of the numbers and , which is , and divide each term by to find the expression inside the parentheses.