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Factorisation - Factorisation using Identities

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Factorisation is the process of writing an algebraic expression as a product of its factors. Using identities is a shortcut method where we recognize the pattern of the expression and match it to a known algebraic formula to find its factors directly.

Identity I: The Square of a Sum. This identity is used for perfect square trinomials where all terms are positive. Visually, this corresponds to a large square with side length (a+b)(a + b), which is composed of a smaller square of area a2a^2, two rectangles each of area abab, and another small square of area b2b^2. The expression a2+2ab+b2a^2 + 2ab + b^2 factors into (a+b)(a+b)(a + b)(a + b) or (a+b)2(a + b)^2.

Identity II: The Square of a Difference. This identity applies to trinomials where the middle term is negative. It follows the pattern a22ab+b2a^2 - 2ab + b^2. Visually, it represents the area of a square with side (ab)(a - b) obtained by subtracting segments of length bb from a larger square of side aa. This factors into (ab)(ab)(a - b)(a - b) or (ab)2(a - b)^2.

Identity III: Difference of Two Squares. This identity is used when an expression consists of two perfect square terms separated by a minus sign (a2b2a^2 - b^2). Visually, imagine taking a square of side aa and cutting out a smaller square of side bb from one corner. The remaining L-shaped area can be sliced and rearranged to form a rectangle with sides (a+b)(a + b) and (ab)(a - b). The factors are (a+b)(ab)(a + b)(a - b).

Identity IV: Product of Binomials with a Common Term. This is used for trinomials of the form x2+(a+b)x+abx^2 + (a + b)x + ab. Here, we look for two numbers whose sum is the coefficient of xx and whose product is the constant term. Visually, this represents a rectangle with dimensions (x+a)(x + a) and (x+b)(x + b) made up of a square x2x^2, two rectangles axax and bxbx, and a small rectangle abab. The factors are (x+a)(x+b)(x + a)(x + b).

Recognition Strategy: To factorise effectively, first check if there is a common factor among all terms. Then, count the terms. If there are two terms, check for the Difference of Squares. If there are three terms, check if the first and last terms are perfect squares to apply Identity I or II; otherwise, try Identity IV.

Verification: After factorising, you can always verify your answer by multiplying the factors back together using the distributive property. The resulting expansion must equal the original algebraic expression.

📐Formulae

a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2

a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2

a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b)

x2+(a+b)x+ab=(x+a)(x+b)x^2 + (a + b)x + ab = (x + a)(x + b)

💡Examples

Problem 1:

Factorise the expression: 9x2+30xy+25y29x^2 + 30xy + 25y^2

Solution:

  1. Observe the terms: The first term 9x29x^2 can be written as (3x)2(3x)^2 and the last term 25y225y^2 can be written as (5y)2(5y)^2. \ 2. Check the middle term: 2×(3x)×(5y)=30xy2 \times (3x) \times (5y) = 30xy. This matches the middle term of the expression. \ 3. Identify the identity: The expression fits the form a2+2ab+b2a^2 + 2ab + b^2 where a=3xa = 3x and b=5yb = 5y. \ 4. Apply Identity I: a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2. \ 5. Write final factors: (3x+5y)2(3x + 5y)^2 or (3x+5y)(3x+5y)(3x + 5y)(3x + 5y).

Explanation:

We recognized the expression as a perfect square trinomial where the first and last terms are squares and the middle term is twice the product of their square roots.

Problem 2:

Factorise the expression: 49p26449p^2 - 64

Solution:

  1. Observe the terms: There are only two terms separated by a minus sign. \ 2. Express as squares: 49p249p^2 can be written as (7p)2(7p)^2 and 6464 can be written as 828^2. \ 3. Identify the identity: The expression fits the form a2b2a^2 - b^2 where a=7pa = 7p and b=8b = 8. \ 4. Apply Identity III: a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b). \ 5. Write final factors: (7p+8)(7p8)(7p + 8)(7p - 8).

Explanation:

Since the expression is a difference of two perfect squares, we used Identity III to split it into the product of the sum and difference of the square roots.