Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
A cube of a number is the result of multiplying the number by itself three times (). This can be visualized as a 3D geometric cube where the length, width, and height are all equal to , and the total number of small unit cubes represents the cube value.
A perfect cube is an integer that is the cube of another integer. In prime factorisation, a perfect cube will always have prime factors that can be grouped into sets of three, known as triplets. For example, in a factor tree for , you will find exactly three branches of .
Finding the cube root is the inverse operation of cubing a number. If , then the cube root of is , denoted by . This is conceptually like knowing the total volume of a cube and trying to find the length of one of its edges.
The prime factorisation method for finding cube roots involves breaking a number down into its simplest prime building blocks. Visually, this is often represented as a vertical ladder or a branching tree until only prime numbers like are left.
To determine the cube root from prime factors, you must group identical factors into triplets. If any factor remains outside of a triplet, the number is not a perfect cube. For a perfect cube, you select exactly one representative from each triplet and multiply them together.
Properties of cubes: The cube of an even number is always even (e.g., ), and the cube of an odd number is always odd (e.g., ). This parity is helpful for quickly checking the validity of a calculated cube root.
The cube root of a negative number is always negative because the product of three negative signs is negative (). For example, because .
📐Formulae
Definition of a Cube:
Cube Root Relation: If , then
Product Law for Cube Roots:
Quotient Law for Cube Roots:
Prime Factorisation Grouping: If , then
💡Examples
Problem 1:
Find the cube root of by prime factorisation.
Solution:
Step 1: Perform prime factorisation of : \n \n \n \n \n \nSo, . \nStep 2: Group the prime factors into triplets: \n. \nStep 3: Take one factor from each triplet: \n. \nStep 4: Calculate the product: \n.
Explanation:
We divide the number by the smallest prime numbers repeatedly. We find that occurs three times and occurs three times. Since all factors form perfect triplets, is a perfect cube, and its root is the product of one prime from each triplet.
Problem 2:
Find the cube root of by prime factorisation.
Solution:
Step 1: Perform prime factorisation of . We check divisibility by and find they are not factors. Checking : \n \n \nSo, . \nStep 2: Group the prime factors into a triplet: \n. \nStep 3: Take one factor from the triplet: \n.
Explanation:
The number is not divisible by small primes like or . Using the divisibility rule for (sum of odd digits minus sum of even digits: ), we identify as a factor. It appears exactly three times, making the cube root.