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Cubes and Cube Roots - Finding Cube Roots by Prime Factorisation

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A cube of a number is the result of multiplying the number by itself three times (n3=n×n×nn^3 = n \times n \times n). This can be visualized as a 3D geometric cube where the length, width, and height are all equal to nn, and the total number of small unit cubes represents the cube value.

A perfect cube is an integer that is the cube of another integer. In prime factorisation, a perfect cube will always have prime factors that can be grouped into sets of three, known as triplets. For example, in a factor tree for 2727, you will find exactly three branches of 33.

Finding the cube root is the inverse operation of cubing a number. If a3=ba^3 = b, then the cube root of bb is aa, denoted by b3=a\sqrt[3]{b} = a. This is conceptually like knowing the total volume of a cube and trying to find the length of one of its edges.

The prime factorisation method for finding cube roots involves breaking a number down into its simplest prime building blocks. Visually, this is often represented as a vertical ladder or a branching tree until only prime numbers like 2,3,5,72, 3, 5, 7 are left.

To determine the cube root from prime factors, you must group identical factors into triplets. If any factor remains outside of a triplet, the number is not a perfect cube. For a perfect cube, you select exactly one representative from each triplet and multiply them together.

Properties of cubes: The cube of an even number is always even (e.g., 43=644^3 = 64), and the cube of an odd number is always odd (e.g., 53=1255^3 = 125). This parity is helpful for quickly checking the validity of a calculated cube root.

The cube root of a negative number is always negative because the product of three negative signs is negative (××=- \times - \times - = -). For example, 83=2\sqrt[3]{-8} = -2 because (2)×(2)×(2)=8(-2) \times (-2) \times (-2) = -8.

📐Formulae

Definition of a Cube: n3=n×n×nn^3 = n \times n \times n

Cube Root Relation: If y=x3y = x^3, then y3=x\sqrt[3]{y} = x

Product Law for Cube Roots: a×b3=a3×b3\sqrt[3]{a \times b} = \sqrt[3]{a} \times \sqrt[3]{b}

Quotient Law for Cube Roots: ab3=a3b3\sqrt[3]{\frac{a}{b}} = \frac{\sqrt[3]{a}}{\sqrt[3]{b}}

Prime Factorisation Grouping: If N=(p×p×p)×(q×q×q)N = (p \times p \times p) \times (q \times q \times q), then N3=p×q\sqrt[3]{N} = p \times q

💡Examples

Problem 1:

Find the cube root of 216216 by prime factorisation.

Solution:

Step 1: Perform prime factorisation of 216216: \n216=2×108216 = 2 \times 108 \n108=2×54108 = 2 \times 54 \n54=2×2754 = 2 \times 27 \n27=3×927 = 3 \times 9 \n9=3×39 = 3 \times 3 \nSo, 216=2×2×2×3×3×3216 = 2 \times 2 \times 2 \times 3 \times 3 \times 3. \nStep 2: Group the prime factors into triplets: \n216=(2×2×2)×(3×3×3)216 = (2 \times 2 \times 2) \times (3 \times 3 \times 3). \nStep 3: Take one factor from each triplet: \n2163=2×3\sqrt[3]{216} = 2 \times 3. \nStep 4: Calculate the product: \n2163=6\sqrt[3]{216} = 6.

Explanation:

We divide the number 216216 by the smallest prime numbers repeatedly. We find that 22 occurs three times and 33 occurs three times. Since all factors form perfect triplets, 216216 is a perfect cube, and its root is the product of one prime from each triplet.

Problem 2:

Find the cube root of 13311331 by prime factorisation.

Solution:

Step 1: Perform prime factorisation of 13311331. We check divisibility by 2,3,5,72, 3, 5, 7 and find they are not factors. Checking 1111: \n1331=11×1211331 = 11 \times 121 \n121=11×11121 = 11 \times 11 \nSo, 1331=11×11×111331 = 11 \times 11 \times 11. \nStep 2: Group the prime factors into a triplet: \n1331=(11×11×11)1331 = (11 \times 11 \times 11). \nStep 3: Take one factor from the triplet: \n13313=11\sqrt[3]{1331} = 11.

Explanation:

The number 13311331 is not divisible by small primes like 22 or 33. Using the divisibility rule for 1111 (sum of odd digits minus sum of even digits: (1+3)(3+1)=0(1+3) - (3+1) = 0), we identify 1111 as a factor. It appears exactly three times, making 1111 the cube root.