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Algebraic Expressions and Identities - Multiplication of Algebraic Expressions

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Multiplying a Monomial by a Monomial: To multiply two monomials, first multiply their numerical coefficients and then multiply their algebraic parts. For variables with the same base, add their exponents according to the law amΓ—an=am+na^m \times a^n = a^{m+n}. Visually, this is equivalent to finding the area of a rectangle where the length and breadth are single algebraic terms, like 3x3x and 5y5y, resulting in a single area of 15xy15xy.

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Multiplying a Monomial by a Polynomial: This process uses the Distributive Law, where the monomial outside the bracket is multiplied by every term inside the bracket. For example, a(b+c)=ab+aca(b + c) = ab + ac. Imagine a large rectangle with height aa and width divided into two parts bb and cc; the total area is the sum of the two smaller rectangles (abab and acac).

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Multiplying a Binomial by a Binomial: Every term in the first binomial must be multiplied by every term in the second binomial. This follows the FOIL method (First, Outer, Inner, Last). Visually, this can be represented by a grid or a large rectangle with dimensions (a+b)(a+b) and (c+d)(c+d), which is split into four distinct rectangular areas: ac,ad,bc,ac, ad, bc, and bdbd.

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Multiplying a Binomial by a Trinomial: Similar to multiplying two binomials, each of the two terms in the binomial is multiplied by each of the three terms in the trinomial, resulting in six initial terms before simplification. You can visualize this as calculating the total surface area of segments or the volume of a structure where one dimension is a sum of three parts.

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Combining Like Terms: After performing multiplication, the expression often contains several terms. You must identify 'like terms'β€”terms that have the exact same variables raised to the same powersβ€”and add or subtract their coefficients to simplify the expression to its final form.

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The Rule of Signs: When multiplying algebraic terms, if both terms have the same sign (both positive or both negative), the product is positive. If the terms have different signs (one positive and one negative), the product is negative. For instance, (βˆ’2x)Γ—(βˆ’3x)=6x2(-2x) \times (-3x) = 6x^2, whereas (2x)Γ—(βˆ’3x)=βˆ’6x2(2x) \times (-3x) = -6x^2.

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Identity-Based Multiplication: Certain products follow specific patterns called Algebraic Identities. These allow for faster multiplication without step-by-step distribution. For example, multiplying (x+3)(x+3)(x+3)(x+3) is a perfect square (x+3)2(x+3)^2, which visually represents the area of a square with side length (x+3)(x+3).

πŸ“Formulae

amΓ—an=am+na^m \times a^n = a^{m+n}

a(b+c)=ab+aca(b + c) = ab + ac

(a+b)(c+d)=a(c+d)+b(c+d)=ac+ad+bc+bd(a + b)(c + d) = a(c + d) + b(c + d) = ac + ad + bc + bd

(x+a)(x+b)=x2+(a+b)x+ab(x + a)(x + b) = x^2 + (a + b)x + ab

(a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2

(aβˆ’b)2=a2βˆ’2ab+b2(a - b)^2 = a^2 - 2ab + b^2

(a+b)(aβˆ’b)=a2βˆ’b2(a + b)(a - b) = a^2 - b^2

πŸ’‘Examples

Problem 1:

Multiply the monomial 4x24x^2 by the trinomial (3x2βˆ’5x+2)(3x^2 - 5x + 2).

Solution:

Step 1: Apply the distributive law by multiplying 4x24x^2 with each term: \n4x2(3x2)+4x2(βˆ’5x)+4x2(2)4x^2(3x^2) + 4x^2(-5x) + 4x^2(2) \nStep 2: Multiply the first terms: 4Γ—3=124 \times 3 = 12 and x2Γ—x2=x2+2=x4β†’12x4x^2 \times x^2 = x^{2+2} = x^4 \rightarrow 12x^4 \nStep 3: Multiply the second terms: 4Γ—βˆ’5=βˆ’204 \times -5 = -20 and x2Γ—x1=x2+1=x3β†’βˆ’20x3x^2 \times x^1 = x^{2+1} = x^3 \rightarrow -20x^3 \nStep 4: Multiply the third terms: 4Γ—2=84 \times 2 = 8 and x2x^2 remains x2β†’8x2x^2 \rightarrow 8x^2 \nStep 5: Combine: 12x4βˆ’20x3+8x212x^4 - 20x^3 + 8x^2

Explanation:

The monomial is distributed to all three terms of the trinomial, following the laws of exponents and signs for each multiplication.

Problem 2:

Multiply the binomials (3x+2)(3x + 2) and (2xβˆ’4)(2x - 4).

Solution:

Step 1: Multiply 3x3x by the entire second binomial: 3x(2xβˆ’4)=6x2βˆ’12x3x(2x - 4) = 6x^2 - 12x \nStep 2: Multiply +2+2 by the entire second binomial: 2(2xβˆ’4)=4xβˆ’82(2x - 4) = 4x - 8 \nStep 3: Write the full expression: 6x2βˆ’12x+4xβˆ’86x^2 - 12x + 4x - 8 \nStep 4: Identify like terms: βˆ’12x-12x and +4x+4x are like terms. \nStep 5: Simplify: 6x2βˆ’8xβˆ’86x^2 - 8x - 8

Explanation:

We use the distributive property twice. After multiplying, we simplify the expression by combining the terms involving xx (βˆ’12x-12x and 4x4x).