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Algebra - Linear sequences

Grade 7IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A sequence is an ordered list of numbers that follow a specific pattern.

A linear sequence (or arithmetic progression) is a sequence where the difference between any two consecutive terms is constant.

The 'common difference' (dd) is the fixed amount added or subtracted to get from one term to the next.

The term number is denoted as 'nn', where n=1n=1 is the first term, n=2n=2 is the second term, and so on.

The nthn^{th} term (general term) is an algebraic rule that allows you to calculate any term in the sequence based on its position.

📐Formulae

Common Difference: d=extTerm2extTerm1d = ext{Term}_2 - ext{Term}_1

nthn^{th} term rule: dn+cdn + c

Zero-term (cc): c=extFirstTermdc = ext{First Term} - d

General position formula: a+(n1)da + (n - 1)d (where aa is the first term)

💡Examples

Problem 1:

Find the nthn^{th} term for the sequence: 5,8,11,14,...5, 8, 11, 14, ...

Solution:

3n+23n + 2

Explanation:

First, find the common difference: 85=38 - 5 = 3, so d=3d = 3. This gives us 3n3n. Next, find the 'zero term' by subtracting the difference from the first term: 53=25 - 3 = 2. Therefore, the nthn^{th} term is 3n+23n + 2.

Problem 2:

A sequence has the nthn^{th} term rule 7n47n - 4. Calculate the 50th50^{th} term.

Solution:

346

Explanation:

To find the 50th50^{th} term, substitute n=50n = 50 into the formula: 7(50)4=3504=3467(50) - 4 = 350 - 4 = 346.

Problem 3:

Determine if 100 is a term in the sequence 4n+34n + 3.

Solution:

No

Explanation:

Set the formula equal to 100: 4n+3=1004n + 3 = 100. Solve for nn: 4n=974n = 97, so n=24.25n = 24.25. Since nn must be a whole number (a position in the sequence), 100 is not a term in this sequence.

Problem 4:

Find the nthn^{th} term for the decreasing sequence: 20,15,10,5,...20, 15, 10, 5, ...

Solution:

5n+25-5n + 25

Explanation:

The common difference is 1520=515 - 20 = -5. The zero term is 20(5)=2520 - (-5) = 25. Thus, the rule is 5n+25-5n + 25.