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Ratio and Proportion - Direct and Inverse Variation

Grade 7ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Variation is the functional relationship between two quantities. If a change in one quantity causes a corresponding change in another, the two quantities are said to be in variation.

Direct Variation: Two quantities xx and yy are in direct variation if they increase or decrease together such that the ratio yx\frac{y}{x} remains constant. Visually, if you plot xx and yy on a coordinate plane, the points will lie on a straight line that passes through the origin (0,0)(0,0), representing a constant rate of growth.

The Constant of Variation (kk) for direct variation is defined by the equation y=kxy = kx. This kk represents the slope of the line in a visual graph; the steeper the line, the larger the value of kk.

Inverse Variation: Two quantities xx and yy are in inverse variation if an increase in xx leads to a proportional decrease in yy (and vice versa). Visually, the graph of an inverse variation is a smooth curve called a hyperbola that gets closer and closer to the xx and yy axes but never actually touches them.

In Inverse Variation, the product of the two variables remains constant: x×y=kx \times y = k. This means that as one value gets very large, the other must get very small to keep the product the same.

To solve variation problems, you can use the Proportion Method. For direct variation, we use the proportion x1y1=x2y2\frac{x_1}{y_1} = \frac{x_2}{y_2}, and for inverse variation, we use the equation x1y1=x2y2x_1 y_1 = x_2 y_2.

Identifying Variation: Always check the relationship first. For example, the number of articles and their total cost is Direct Variation (more articles = more cost), while the number of workers and the time taken to finish a task is Inverse Variation (more workers = less time).

📐Formulae

Direct Variation: y=kxy = kx where kk is a constant

Constant of Direct Variation: k=yxk = \frac{y}{x}

Direct Variation Proportion: x1y1=x2y2\frac{x_1}{y_1} = \frac{x_2}{y_2}

Inverse Variation: y=kxy = \frac{k}{x} or xy=kxy = k where kk is a constant

Inverse Variation Equation: x1y1=x2y2x_1 y_1 = x_2 y_2

💡Examples

Problem 1:

If 1515 notebooks cost Rs.450Rs. 450, find the cost of 2424 such notebooks.

Solution:

Step 1: Identify the variation. Since more notebooks will cost more money, this is a case of Direct Variation. Step 2: Let x1=15x_1 = 15, y1=450y_1 = 450, and x2=24x_2 = 24. Let the unknown cost be y2y_2. Step 3: Use the formula x1y1=x2y2\frac{x_1}{y_1} = \frac{x_2}{y_2}. 15450=24y2\frac{15}{450} = \frac{24}{y_2} Step 4: Solve for y2y_2 by cross-multiplication: 15×y2=24×45015 \times y_2 = 24 \times 450 y2=24×45015y_2 = \frac{24 \times 450}{15} y2=24×30=720y_2 = 24 \times 30 = 720. Final Answer: The cost of 2424 notebooks is Rs.720Rs. 720.

Explanation:

We used the direct variation ratio because the cost per unit remains constant regardless of the number of items bought.

Problem 2:

A group of 1212 men can complete a piece of work in 88 days. How many days will it take 1616 men to complete the same work?

Solution:

Step 1: Identify the variation. More men will take less time to complete the same work, so this is Inverse Variation. Step 2: Let x1=12x_1 = 12 (men), y1=8y_1 = 8 (days), and x2=16x_2 = 16 (men). Let the unknown days be y2y_2. Step 3: Use the inverse variation formula x1y1=x2y2x_1 y_1 = x_2 y_2. 12×8=16×y212 \times 8 = 16 \times y_2 Step 4: Solve for y2y_2: 96=16×y296 = 16 \times y_2 y2=9616y_2 = \frac{96}{16} y2=6y_2 = 6. Final Answer: It will take 1616 men 66 days to complete the work.

Explanation:

In inverse variation, the total 'man-days' (the product of people and time) stays constant. Here, the total work is 9696 man-days.