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Data Handling - Probability: Basic concepts and simple problems

Grade 7ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A Random Experiment is an action where the result cannot be predicted with total certainty before it happens, such as tossing a coin or rolling a die. Visualise a coin spinning in the air; until it lands and stops, you do not know if it will show Heads or Tails.

An Outcome is a possible result of a single trial of an experiment. For example, if you roll a six-sided die, the possible outcomes are 1,2,3,4,5,1, 2, 3, 4, 5, or 66. Imagine the die face-up on a table showing a specific number of dots.

The Sample Space is the set of all possible outcomes of an experiment, usually denoted by SS. For a coin toss, the sample space is S={H,T}S = \{H, T\}. Visualise this as a boundary or a box that contains every single result that could possibly happen.

An Event is a specific outcome or a collection of outcomes that we are interested in, which is a subset of the sample space. For instance, in rolling a die, 'getting an even number' is an event containing the outcomes {2,4,6}\{2, 4, 6\}.

Equally Likely Outcomes occur when every outcome in the sample space has the same chance of happening. Imagine a fair spinner divided into four equal quarters of different colors; because the area for each color is the same, the needle is equally likely to land on any color.

The Probability of an Event, denoted as P(E)P(E), is a numerical measure of the likelihood that the event will occur. It is always a value between 00 and 11 inclusive. Imagine a 'Probability Scale' line where 00 represents an 'Impossible Event' (like drawing a blue card from a deck of only red cards) and 11 represents a 'Certain Event' (like the sun rising).

An Impossible Event has a probability of 00. For example, the probability of rolling a 77 on a standard six-sided die is 00 because the faces are only numbered 11 through 66.

A Sure or Certain Event has a probability of 11. For example, if a bag contains only red balls, the probability of drawing a red ball is 11 because there is no other possibility.

📐Formulae

P(E)=Number of outcomes favorable to ETotal number of possible outcomesP(E) = \frac{\text{Number of outcomes favorable to } E}{\text{Total number of possible outcomes}}

0P(E)10 \le P(E) \le 1

P(Sure Event)=1P(\text{Sure Event}) = 1

P(Impossible Event)=0P(\text{Impossible Event}) = 0

Total Outcomes for a Die=6\text{Total Outcomes for a Die} = 6

Total Outcomes for a Coin=2\text{Total Outcomes for a Coin} = 2

💡Examples

Problem 1:

A bag contains 44 red marbles, 33 blue marbles, and 55 green marbles. If one marble is drawn at random, what is the probability that it is a blue marble?

Solution:

Step 1: Calculate the total number of possible outcomes. Total outcomes=4 (red)+3 (blue)+5 (green)=12\text{Total outcomes} = 4 \text{ (red)} + 3 \text{ (blue)} + 5 \text{ (green)} = 12 Step 2: Identify the number of favorable outcomes for the event 'drawing a blue marble'. Favorable outcomes=3\text{Favorable outcomes} = 3 Step 3: Apply the probability formula: P(Blue)=Number of favorable outcomesTotal number of outcomes=312P(\text{Blue}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{12} Step 4: Simplify the fraction: P(Blue)=14P(\text{Blue}) = \frac{1}{4}

Explanation:

To find the probability, we first find the sum of all items to get the total possibilities. Then, we identify how many items match our specific requirement (blue) and express it as a fraction of the total.

Problem 2:

A standard six-sided die is thrown once. Find the probability of getting a prime number.

Solution:

Step 1: List the sample space of a die. S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\} Total outcomes=6\text{Total outcomes} = 6 Step 2: Identify the prime numbers in the sample space. Prime numbers are {2,3,5}\text{Prime numbers are } \{2, 3, 5\} Number of favorable outcomes=3\text{Number of favorable outcomes} = 3 Step 3: Calculate the probability: P(Prime)=36P(\text{Prime}) = \frac{3}{6} Step 4: Simplify the result: P(Prime)=12P(\text{Prime}) = \frac{1}{2}

Explanation:

In this problem, we identify all possible results of a die roll. We then pick out the prime numbers (numbers with exactly two factors: 1 and itself) to find our favorable outcomes and divide by the total number of faces on the die.