Review the key concepts, formulae, and examples before starting your quiz.
๐Concepts
A Linear Equation in one variable is a mathematical statement where two expressions are equal, and the highest power of the variable (usually , , or ) is . Visually, this can be represented as a balance scale where the left-hand side (LHS) and right-hand side (RHS) must stay level.
The Principle of Equality states that you can add, subtract, multiply, or divide (by a non-zero number) the same value on both sides of the equation without changing the equality. Imagine adding or removing equal weights from both pans of a balance scale; the scale remains perfectly horizontal.
Transposition is the process of moving a term from one side of the equation to the other. When a term moves across the equal sign (), its operation changes: becomes , becomes , becomes , and becomes . Visually, think of the equal sign as a 'magic gate' that flips the sign of any term passing through it.
Solving Equations with Brackets involves using the Distributive Property, where a term outside the parentheses is multiplied by every term inside, such as . Visually, this is like distributing a gift to every person inside a room.
Cross-Multiplication is used when the equation is in the form of a proportion, like . We multiply the numerator of the first side by the denominator of the second side and vice-versa, resulting in . Visually, draw an 'X' shape connecting the top of one side to the bottom of the other.
Translating Word Problems involves identifying keywords: 'sum' or 'increased by' means , 'difference' or 'diminished by' means , 'product' or 'times' means , and 'is' or 'results in' means . Visualizing the problem as a flow diagram helps in constructing the algebraic equation correctly.
๐Formulae
General form of a linear equation: (where )
Distributive Property:
Transposition Rule (Addition/Subtraction): If , then
Transposition Rule (Multiplication/Division): If , then
Cross Multiplication Formula:
๐กExamples
Problem 1:
Solve for :
Solution:
Step 1: Expand the brackets on both sides: Step 2: Transpose to the LHS and to the RHS: Step 3: Simplify both sides: Step 4: Divide both sides by : Verification: and . LHS = RHS.
Explanation:
We first use the distributive property to remove parentheses, then group variable terms on one side and constant terms on the other using transposition to find the value of .
Problem 2:
The sum of three consecutive integers is . Find the integers.
Solution:
Step 1: Let the three consecutive integers be , , and . Step 2: According to the problem, their sum is : Step 3: Combine like terms: Step 4: Transpose to the RHS: Step 5: Solve for : Step 6: Find the other two integers: and . The integers are .
Explanation:
We represent the unknown values using a single variable . Since they are consecutive, each is greater than the previous. We then form a linear equation based on the given sum and solve for the first integer.