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Algebra - Solving Equations and Word Problems

Grade 7ICSE

Review the key concepts, formulae, and examples before starting your quiz.

๐Ÿ”‘Concepts

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A Linear Equation in one variable is a mathematical statement where two expressions are equal, and the highest power of the variable (usually xx, yy, or zz) is 11. Visually, this can be represented as a balance scale where the left-hand side (LHS) and right-hand side (RHS) must stay level.

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The Principle of Equality states that you can add, subtract, multiply, or divide (by a non-zero number) the same value on both sides of the equation without changing the equality. Imagine adding or removing equal weights from both pans of a balance scale; the scale remains perfectly horizontal.

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Transposition is the process of moving a term from one side of the equation to the other. When a term moves across the equal sign (==), its operation changes: ++ becomes โˆ’-, โˆ’- becomes ++, ร—\times becomes รท\div, and รท\div becomes ร—\times. Visually, think of the equal sign as a 'magic gate' that flips the sign of any term passing through it.

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Solving Equations with Brackets involves using the Distributive Property, where a term outside the parentheses is multiplied by every term inside, such as a(b+c)=ab+aca(b + c) = ab + ac. Visually, this is like distributing a gift to every person inside a room.

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Cross-Multiplication is used when the equation is in the form of a proportion, like ab=cd\frac{a}{b} = \frac{c}{d}. We multiply the numerator of the first side by the denominator of the second side and vice-versa, resulting in ad=bcad = bc. Visually, draw an 'X' shape connecting the top of one side to the bottom of the other.

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Translating Word Problems involves identifying keywords: 'sum' or 'increased by' means ++, 'difference' or 'diminished by' means โˆ’-, 'product' or 'times' means ร—\times, and 'is' or 'results in' means ==. Visualizing the problem as a flow diagram helps in constructing the algebraic equation correctly.

๐Ÿ“Formulae

General form of a linear equation: ax+b=0ax + b = 0 (where aโ‰ 0a \neq 0)

Distributive Property: a(bx+c)=abx+aca(bx + c) = abx + ac

Transposition Rule (Addition/Subtraction): If x+a=bx + a = b, then x=bโˆ’ax = b - a

Transposition Rule (Multiplication/Division): If ax=bax = b, then x=bax = \frac{b}{a}

Cross Multiplication Formula: ax+bcx+d=pqโ€…โ€ŠโŸนโ€…โ€Šq(ax+b)=p(cx+d)\frac{ax + b}{cx + d} = \frac{p}{q} \implies q(ax + b) = p(cx + d)

๐Ÿ’กExamples

Problem 1:

Solve for xx: 4(xโˆ’3)=2(x+5)4(x - 3) = 2(x + 5)

Solution:

Step 1: Expand the brackets on both sides: 4xโˆ’12=2x+104x - 12 = 2x + 10 Step 2: Transpose 2x2x to the LHS and โˆ’12-12 to the RHS: 4xโˆ’2x=10+124x - 2x = 10 + 12 Step 3: Simplify both sides: 2x=222x = 22 Step 4: Divide both sides by 22: x=222=11x = \frac{22}{2} = 11 Verification: 4(11โˆ’3)=4(8)=324(11-3) = 4(8) = 32 and 2(11+5)=2(16)=322(11+5) = 2(16) = 32. LHS = RHS.

Explanation:

We first use the distributive property to remove parentheses, then group variable terms on one side and constant terms on the other using transposition to find the value of xx.

Problem 2:

The sum of three consecutive integers is 5151. Find the integers.

Solution:

Step 1: Let the three consecutive integers be xx, x+1x + 1, and x+2x + 2. Step 2: According to the problem, their sum is 5151: x+(x+1)+(x+2)=51x + (x + 1) + (x + 2) = 51 Step 3: Combine like terms: 3x+3=513x + 3 = 51 Step 4: Transpose 33 to the RHS: 3x=51โˆ’3=483x = 51 - 3 = 48 Step 5: Solve for xx: x=483=16x = \frac{48}{3} = 16 Step 6: Find the other two integers: x+1=17x + 1 = 17 and x+2=18x + 2 = 18. The integers are 16,17,1816, 17, 18.

Explanation:

We represent the unknown values using a single variable xx. Since they are consecutive, each is 11 greater than the previous. We then form a linear equation based on the given sum and solve for the first integer.