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Geometry and Measurement - Geometric Transformations (Translation, Reflection, Rotation)

Grade 7IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Transformation Basics: A transformation is a process that maps an original geometric figure, called the 'pre-image', onto a new figure called the 'image'. In Grade 7, we focus on isometric transformations (translations, reflections, and rotations) where the image remains congruent to the pre-image, meaning size and shape do not change. Visually, the image is often labeled with prime notation, such as point AA becoming AA'.

Translation (Sliding): A translation moves every point of a figure the same distance in a specified direction without changing its orientation. Visually, it is like sliding a tile across a floor. It is often described using a column vector (ab)\begin{pmatrix} a \\ b \end{pmatrix}, where aa indicates horizontal movement (right is positive, left is negative) and bb indicates vertical movement (up is positive, down is negative).

Reflection (Flipping): A reflection flips a figure over a line called the 'axis of reflection' or 'mirror line'. Visually, the image is a mirror reflection of the pre-image. Every point and its image are equidistant from the line of reflection, and the line segment connecting them is perpendicular to the mirror line. Reflection changes the orientation of the shape (e.g., a 'right-facing' shape becomes 'left-facing').

Rotation (Turning): A rotation turns a figure around a fixed point called the 'center of rotation'. To describe a rotation, you need three pieces of information: the center of rotation (often the origin (0,0)(0,0)), the angle of rotation (e.g., 9090^\circ, 180180^\circ), and the direction (clockwise or counter-clockwise). Visually, every point on the shape moves along a circular path around the center.

Lines of Reflection: Common mirror lines include the xx-axis (the horizontal line where y=0y = 0), the yy-axis (the vertical line where x=0x = 0), and diagonal lines like y=xy = x or y=xy = -x. Visually, if you fold your graph paper along these lines, the pre-image will land perfectly on top of the image.

Properties of Isometry: Under translation, reflection, and rotation, the following properties are preserved (invariant): side lengths, angle measures, perimeter, and area. The only thing that changes is the position or orientation of the figure. Visually, the 'twin' shapes look identical in size and form, just placed differently on the coordinate plane.

📐Formulae

Translation Rule: (x,y)(x+a,y+b)(x, y) \rightarrow (x + a, y + b) for a vector (ab)\begin{pmatrix} a \\ b \end{pmatrix}

Reflection in the xx-axis: (x,y)(x,y)(x, y) \rightarrow (x, -y)

Reflection in the yy-axis: (x,y)(x,y)(x, y) \rightarrow (-x, y)

Reflection in the line y=xy = x: (x,y)(y,x)(x, y) \rightarrow (y, x)

Rotation 9090^\circ counter-clockwise about the origin: (x,y)(y,x)(x, y) \rightarrow (-y, x)

Rotation 180180^\circ about the origin: (x,y)(x,y)(x, y) \rightarrow (-x, -y)

Rotation 270270^\circ counter-clockwise (or 9090^\circ clockwise) about the origin: (x,y)(y,x)(x, y) \rightarrow (y, -x)

💡Examples

Problem 1:

A triangle has vertices A(1,2)A(1, 2), B(4,2)B(4, 2), and C(1,5)C(1, 5). Translate this triangle using the vector (34)\begin{pmatrix} -3 \\ 4 \end{pmatrix} and find the coordinates of the image.

Solution:

  1. Identify the translation values: a=3a = -3 (move 3 units left) and b=4b = 4 (move 4 units up).
  2. Apply the rule (x,y)(x3,y+4)(x, y) \rightarrow (x - 3, y + 4) to each vertex:
  • For A(1,2)A(1, 2): A(13,2+4)=A(2,6)A'(1 - 3, 2 + 4) = A'(-2, 6)
  • For B(4,2)B(4, 2): B(43,2+4)=B(1,6)B'(4 - 3, 2 + 4) = B'(1, 6)
  • For C(1,5)C(1, 5): C(13,5+4)=C(2,9)C'(1 - 3, 5 + 4) = C'(-2, 9)
  1. The coordinates of the image are A(2,6)A'(-2, 6), B(1,6)B'(1, 6), and C(2,9)C'(-2, 9).

Explanation:

To translate a shape, we add the horizontal component of the vector to the xx-coordinates and the vertical component to the yy-coordinates of all vertices.

Problem 2:

Point PP is located at (3,5)(3, -5). Find the coordinates of the image PP' after a reflection in the yy-axis, followed by a rotation of 180180^\circ about the origin.

Solution:

Step 1: Reflect P(3,5)P(3, -5) in the yy-axis. The rule for reflection in the yy-axis is (x,y)(x,y)(x, y) \rightarrow (-x, y). P(3,5)Ptemp(3,5)P(3, -5) \rightarrow P_{temp}(-3, -5).

Step 2: Rotate the new point Ptemp(3,5)P_{temp}(-3, -5) by 180180^\circ about the origin. The rule for a 180180^\circ rotation is (x,y)(x,y)(x, y) \rightarrow (-x, -y). Ptemp(3,5)P((3),(5))=P(3,5)P_{temp}(-3, -5) \rightarrow P'(-(-3), -(-5)) = P'(3, 5).

Final Answer: P(3,5)P'(3, 5).

Explanation:

This is a composite transformation. We apply the first rule (reflection) to the original point to get an intermediate point, then apply the second rule (rotation) to that intermediate point to find the final image.