krit.club logo

Algebra - Introduction to Algebraic Expressions

Grade 7IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Variables and Constants: A variable is a symbol, usually a letter like xx, yy, or nn, that represents an unknown number or a value that can change. A constant is a fixed number that does not change, such as 55, 10-10, or 3.53.5. Visually, you can imagine a variable as an empty box where different numbers can be placed, while a constant is a solid, unchangeable block.

Terms, Coefficients, and Operators: An algebraic expression is made of 'terms' separated by plus or minus signs. In the term 7x7x, 77 is the 'coefficient' (the numerical factor) and xx is the variable. If a term is just a number like +12+12, it is a constant term. Visually, think of an expression like 4x3y+54x - 3y + 5 as a train where each carriage is a separate term (4x4x, 3y-3y, and +5+5).

Like and Unlike Terms: Like terms are terms that have the exact same variables raised to the same powers, such as 3a3a and 10a10a. Unlike terms have different variables or different exponents, such as 2x2x and 2x22x^2. Visually, you can group like terms by drawing circles around all 'xx' terms and squares around all 'yy' terms to see which ones can be combined.

Simplifying Expressions: To simplify an expression, you combine like terms by adding or subtracting their coefficients while keeping the variable part the same. For example, 5x+2x5x + 2x becomes 7x7x. Visually, this is like putting all the 'apple' blocks in one pile and all the 'orange' blocks in another.

Evaluating Expressions: This is the process of finding the numerical value of an expression by substituting specific numbers for the variables. For example, to evaluate x+5x + 5 when x=3x = 3, you replace xx with 33 to get 3+5=83 + 5 = 8. Visually, think of the variable as a placeholder or a 'window' where you slot in a specific number to see the final result.

The Distributive Property: This property allows you to multiply a single term by every term inside a set of parentheses, written as a(b+c)=ab+aca(b + c) = ab + ac. Visually, imagine an arrow drawn from the number outside the bracket to each individual term inside, showing that the multiplier is shared across all components within the group.

Algebraic Translation: This involves converting word problems into math symbols. For instance, 'five more than a number' translates to n+5n + 5, and 'twice a number' translates to 2n2n. Visually, you can create a 'translation table' where words like 'sum' or 'increased by' map to the ++ sign, and 'product' maps to the ×\times sign.

📐Formulae

Commutative Property of Addition: a+b=b+aa + b = b + a

Commutative Property of Multiplication: a×b=b×aa \times b = b \times a

Associative Property: (a+b)+c=a+(b+c)(a + b) + c = a + (b + c)

Distributive Property: a(b+c)=ab+aca(b + c) = ab + ac

Identity Property of Addition: a+0=aa + 0 = a

Identity Property of Multiplication: a×1=aa \times 1 = a

Term Structure: coefficient×variablecoefficient \times variable

💡Examples

Problem 1:

Simplify the expression: 4x+7y2x+3+5y14x + 7y - 2x + 3 + 5y - 1

Solution:

Step 1: Identify and group like terms. (4x2x)+(7y+5y)+(31)(4x - 2x) + (7y + 5y) + (3 - 1) Step 2: Combine the coefficients of the variable terms. (42)x+(7+5)y+(31)(4 - 2)x + (7 + 5)y + (3 - 1) Step 3: Simplify the arithmetic. 2x+12y+22x + 12y + 2

Explanation:

We group the terms with xx, the terms with yy, and the constant numbers separately. Then we perform the addition or subtraction on each group to reach the simplest form.

Problem 2:

Evaluate the expression 3(n4)+2n3(n - 4) + 2n when n=6n = 6.

Solution:

Step 1: Substitute 66 for every instance of nn in the expression. 3(64)+2(6)3(6 - 4) + 2(6) Step 2: Solve the operation inside the parentheses first (BODMAS/PEMDAS). 3(2)+2(6)3(2) + 2(6) Step 3: Perform the multiplications. 6+126 + 12 Step 4: Add the final results. 1818

Explanation:

Substitution replaces the variable with a known value. Following the order of operations ensures the calculation is performed correctly, starting with the brackets.