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The Triangle and its Properties - Angle Sum Property of a Triangle

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Angle Sum Property states that the sum of the measures of the three interior angles of any triangle is always 180180^{\circ}. This is a fundamental rule that applies to all triangles regardless of their size or shape.

To visualize this property, imagine cutting out the three corners of a paper triangle (labeled A\angle A, B\angle B, and C\angle C) and arranging them side-by-side at a single point. The three angles will perfectly form a straight line, which represents a straight angle of 180180^{\circ}.

In a right-angled triangle, one angle is always 9090^{\circ}, which is represented visually by a small square at the vertex. This means the sum of the other two acute angles must be 18090=90180^{\circ} - 90^{\circ} = 90^{\circ}. These two angles are called complementary angles.

In an equilateral triangle, all three sides are equal and all three interior angles are equal. Since the total sum must be 180180^{\circ}, each individual angle must measure exactly 1803=60\frac{180^{\circ}}{3} = 60^{\circ}.

In an isosceles triangle, two sides are of equal length, and the angles opposite these sides are also equal. If the measure of the non-equal angle (the vertex angle) is known, the other two angles can be found by subtracting the known angle from 180180^{\circ} and dividing the result by 22.

A triangle cannot have more than one right angle or more than one obtuse angle (an angle greater than 9090^{\circ}). If it did, the sum of just those two angles would already meet or exceed 180180^{\circ}, leaving no room for the third angle.

The property can be verified by drawing a line through one vertex of a triangle that is parallel to the opposite side. Using the properties of parallel lines and transversal (alternate interior angles), the three angles at the vertex will lie on a straight line, summing to 180180^{\circ}.

📐Formulae

A+B+C=180\angle A + \angle B + \angle C = 180^{\circ}

Third Angle=180(Sum of the other two angles)\text{Third Angle} = 180^{\circ} - (\text{Sum of the other two angles})

In an Equilateral Triangle: x+x+x=180    3x=180    x=60\text{In an Equilateral Triangle: } x + x + x = 180^{\circ} \implies 3x = 180^{\circ} \implies x = 60^{\circ}

In a Right-Angled Triangle: 90+1+2=180\text{In a Right-Angled Triangle: } 90^{\circ} + \angle 1 + \angle 2 = 180^{\circ}

💡Examples

Problem 1:

In XYZ\triangle XYZ, the measure of X=55\angle X = 55^{\circ} and the measure of Y=65\angle Y = 65^{\circ}. Find the measure of Z\angle Z.

Solution:

  1. According to the Angle Sum Property, X+Y+Z=180\angle X + \angle Y + \angle Z = 180^{\circ}.
  2. Substitute the given values into the equation: 55+65+Z=18055^{\circ} + 65^{\circ} + \angle Z = 180^{\circ}.
  3. Calculate the sum of the known angles: 120+Z=180120^{\circ} + \angle Z = 180^{\circ}.
  4. Subtract 120120^{\circ} from both sides to find the unknown angle: Z=180120\angle Z = 180^{\circ} - 120^{\circ}.
  5. Final result: Z=60\angle Z = 60^{\circ}.

Explanation:

To find a missing angle in a triangle, we subtract the sum of the two known angles from 180180^{\circ}.

Problem 2:

One of the acute angles of a right-angled triangle is 4242^{\circ}. Find the measure of the other acute angle.

Solution:

  1. In a right-angled triangle, one angle is always 9090^{\circ}. Let the three angles be 9090^{\circ}, 4242^{\circ}, and xx.
  2. Use the Angle Sum Property: 90+42+x=18090^{\circ} + 42^{\circ} + x = 180^{\circ}.
  3. Simplify the equation: 132+x=180132^{\circ} + x = 180^{\circ}.
  4. Solve for xx: x=180132x = 180^{\circ} - 132^{\circ}.
  5. Final result: x=48x = 48^{\circ}.

Explanation:

Since one angle is fixed at 9090^{\circ}, the other two angles must add up to 9090^{\circ}. We can simply subtract the given acute angle from 9090^{\circ} to find the answer: 9042=4890^{\circ} - 42^{\circ} = 48^{\circ}.