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Simple Equations - Setting up an equation

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

An equation is a mathematical statement of equality containing one or more variables. It can be visualized as a balanced weighing scale where the '=' sign acts as the fulcrum (pivot). For the scale to stay level, the total value on the Left Hand Side (LHS) must be exactly equal to the total value on the Right Hand Side (RHS).

Variables are unknown values represented by letters like x,y,z,l,m,x, y, z, l, m, or nn. Think of a variable as an 'empty box' whose contents we need to find. In contrast, constants are fixed numerical values like 5,10,5, -10, or 12\frac{1}{2} that do not change.

Setting up an equation involves translating verbal phrases into mathematical operations. Phrases like 'sum of' or 'added to' imply addition (++), 'difference between' or 'subtracted from' imply subtraction (-), 'times' or 'product' imply multiplication (×\times), and 'divided by' implies division (÷\div).

The phrase 'is' or 'gives' or 'results in' represents the equals sign (==) in an equation. For example, 'The sum of xx and 55 is 1212' translates to x+5=12x + 5 = 12. Visually, this means a block of length xx joined with a block of length 55 matches a single block of length 1212 exactly.

In word problems, identifying the unknown quantity is the first step. We assign a variable to this unknown. For instance, if a problem asks for 'the number of marbles Rahul has,' we let that number be mm. Every other piece of information in the problem is then written in relation to mm.

Equations can involve multiple operations. For example, '3 more than twice a number is 11' involves both multiplication and addition. You first multiply the variable by 2 (2x2x) and then add 3 (2x+32x + 3). The final equation is 2x+3=112x + 3 = 11.

An equation remains balanced if you perform the same operation on both sides. Imagine adding an equal weight to both pans of a scale; the scale remains balanced. Similarly, if x+2=5x + 2 = 5, then (x+2)2=52(x + 2) - 2 = 5 - 2 also holds true.

📐Formulae

ax+b=cax + b = c (General form of a simple equation in one variable)

Sum+\text{Sum} \Rightarrow +

Difference\text{Difference} \Rightarrow -

Product×\text{Product} \Rightarrow \times

Quotient÷\text{Quotient} \Rightarrow \div

Result/Is=\text{Result/Is} \Rightarrow =

Perimeter of a rectangle=2(l+b)\text{Perimeter of a rectangle} = 2(l + b)

Area of a rectangle=l×b\text{Area of a rectangle} = l \times b

💡Examples

Problem 1:

Set up an equation for the following: 'Ten subtracted from eight times a number nn gives 38.'

Solution:

Step 1: Identify the variable: The number is nn. Step 2: Translate 'eight times a number': 8×n=8n8 \times n = 8n. Step 3: Translate 'ten subtracted from': 8n108n - 10. Step 4: Translate 'gives 38': =38= 38. Final Equation: 8n10=388n - 10 = 38.

Explanation:

The phrase 'subtracted from' means the 10 must be taken away from the product of 8 and nn. The word 'gives' indicates the total result.

Problem 2:

Laxmi's father is 49 years old. He is 4 years older than three times Laxmi's age. Set up an equation to find Laxmi's age.

Solution:

Step 1: Let Laxmi's age be yy years. Step 2: Three times Laxmi's age is 3y3y. Step 3: 4 years older than three times her age is 3y+43y + 4. Step 4: This expression equals her father's age, which is 49. Final Equation: 3y+4=493y + 4 = 49.

Explanation:

We identify Laxmi's age as the unknown variable. We construct the father's age using the given conditions (33 times and 44 more) and equate it to his actual age of 49.