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Perimeter and Area - Perimeter and Area of Squares and Rectangles

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Perimeter is the total length of the boundary of a closed figure. For a square or rectangle, you can visualize this as the length of a wire needed to form the shape's outline.

Area measures the surface region enclosed by the boundaries of a closed figure. If you were to tile a floor, the number of unit squares required to cover the entire floor represents its area.

A Square is a quadrilateral where all four sides are equal and every interior angle is 9090^\circ. Visually, it is perfectly symmetrical, and its perimeter is simply four times the length of one side.

A Rectangle is a quadrilateral where opposite sides are equal and every interior angle is 9090^\circ. It has a longer dimension called length (ll) and a shorter dimension called breadth (bb).

Units of Measurement: Perimeter is measured in linear units like cmcm or mm. Area is measured in square units like cm2cm^{2} or m2m^{2}. Note that 1m2=10,000cm21 m^{2} = 10,000 cm^{2} because area involves two dimensions (100cm×100cm100 cm \times 100 cm).

To find a missing dimension of a rectangle when the area and one side are given, use the inverse operation: length=Areabreadthlength = \frac{Area}{breadth} or breadth=Arealengthbreadth = \frac{Area}{length}.

The perimeter and area change differently when side lengths are adjusted. For example, doubling the side of a square doubles its perimeter but quadruples its area (2s×2s=4s22s \times 2s = 4s^{2}).

📐Formulae

Perimeter of a Square = 4×s4 \times s (where ss is the side)

Area of a Square = s×s=s2s \times s = s^{2}

Perimeter of a Rectangle = 2×(l+b)2 \times (l + b) (where ll is length and bb is breadth)

Area of a Rectangle = l×bl \times b

Side of a Square = Perimeter4\frac{Perimeter}{4}

Side of a Square = Area\sqrt{Area}

💡Examples

Problem 1:

A square park has a side length of 15m15 m. Find the total cost of fencing the park at a rate of 2020 per meter.

Solution:

Step 1: Identify the side of the square, s=15ms = 15 m. Step 2: Calculate the perimeter (boundary) for fencing. Perimeter=4×s=4×15=60mPerimeter = 4 \times s = 4 \times 15 = 60 m Step 3: Calculate the total cost. Cost=Perimeter×Rate=60×20=1200Cost = Perimeter \times Rate = 60 \times 20 = 1200 Final Answer: The total cost of fencing is 12001200.

Explanation:

To find the cost of fencing, we first need the total length of the boundary, which is the perimeter. Once the perimeter is found in meters, we multiply it by the cost per meter.

Problem 2:

The area of a rectangular hall is 96m296 m^{2}. If the length of the hall is 12m12 m, find its breadth and its perimeter.

Solution:

Step 1: Use the area formula to find the breadth (bb). Area=l×b    96=12×bArea = l \times b \implies 96 = 12 \times b b=9612=8mb = \frac{96}{12} = 8 m Step 2: Use the length (12m12 m) and breadth (8m8 m) to find the perimeter. Perimeter=2×(l+b)=2×(12+8)Perimeter = 2 \times (l + b) = 2 \times (12 + 8) Perimeter=2×20=40mPerimeter = 2 \times 20 = 40 m Final Answer: The breadth is 8m8 m and the perimeter is 40m40 m.

Explanation:

We start by rearranging the area formula to solve for the unknown breadth. Once both dimensions are known, we apply the perimeter formula for a rectangle.