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Perimeter and Area - Circumference and Area of a Circle

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Concept 1: Definition of a Circle and its Center. A circle is a simple closed curve where every point on the boundary is at an equal distance from a fixed point inside called the center. Visually, you can imagine a compass where the needle stays fixed at the center while the pencil moves to draw the round boundary.

Concept 2: Radius and Diameter. The radius (rr) is the distance from the center to any point on the circle's edge. The diameter (dd) is a straight line that passes through the center and connects two points on the circle. Visually, the diameter is a straight line cutting the circle into two equal halves, and mathematically, it is twice the radius: d=2rd = 2r.

Concept 3: Circumference (CC). The circumference is the distance around the edge of the circle, effectively its perimeter. If you imagine a circular wheel rolling one complete revolution, the distance it travels on the ground is equal to its circumference.

Concept 4: The Constant Pi (π\pi). For every circle, the ratio of its circumference to its diameter is always constant. This constant is denoted by the Greek letter π\pi. Since Cd=π\frac{C}{d} = \pi, we derive the formula C=πdC = \pi d. For calculations, we usually use π227\pi \approx \frac{22}{7} or π3.14\pi \approx 3.14.

Concept 5: Area of a Circle (AA). The area is the measure of the region enclosed inside the circle's boundary. Visually, it is the flat surface area covered by the circle. The formula is derived as A=πr2A = \pi r^2.

Concept 6: Relationship between Sectors and Area. If a circle is cut into several small sectors (like thin pizza slices) and rearranged, they form a shape resembling a rectangle. The height of this rectangle is the radius (rr) and the base length is half the circumference (πr\pi r), leading to the area formula: Area=length×breadth=πr×r=πr2Area = \text{length} \times \text{breadth} = \pi r \times r = \pi r^2.

Concept 7: Semi-circle Perimeter and Area. A semi-circle is half of a full circle, visually appearing like a protractor. Its area is 12πr2\frac{1}{2} \pi r^2. Its perimeter consists of the curved arc (πr\pi r) plus the straight diameter (2r2r), giving the total perimeter as πr+2r\pi r + 2r.

📐Formulae

Diameter: d=2rd = 2r

Circumference: C=2πrC = 2 \pi r

Circumference in terms of diameter: C=πdC = \pi d

Area of a Circle: A=πr2A = \pi r^2

Value of Pi: π227\pi \approx \frac{22}{7} or 3.143.14

💡Examples

Problem 1:

Find the circumference and the area of a circle with a radius of 1414 cm. (Take π=227\pi = \frac{22}{7})

Solution:

Given: Radius r=14r = 14 cm, π=227\pi = \frac{22}{7}.

Step 1: Find Circumference (CC). C=2πrC = 2 \pi r C=2×227×14C = 2 \times \frac{22}{7} \times 14 C=2×22×2C = 2 \times 22 \times 2 C=88 cmC = 88 \text{ cm}

Step 2: Find Area (AA). A=πr2A = \pi r^2 A=227×14×14A = \frac{22}{7} \times 14 \times 14 A=22×2×14A = 22 \times 2 \times 14 A=44×14A = 44 \times 14 A=616 cm2A = 616 \text{ cm}^2

Explanation:

To solve this, we substitute the given radius into the standard formulas for circumference and area. We simplify by canceling out the common factor 77 from the denominator and the numerator (1414).

Problem 2:

The circumference of a circular sheet is 154154 m. Find its radius and area. (Take π=227\pi = \frac{22}{7})

Solution:

Given: Circumference C=154C = 154 m.

Step 1: Find the radius (rr). C=2πrC = 2 \pi r 154=2×227×r154 = 2 \times \frac{22}{7} \times r 154=447×r154 = \frac{44}{7} \times r r=154×744r = \frac{154 \times 7}{44} r=7×72=492=24.5 mr = \frac{7 \times 7}{2} = \frac{49}{2} = 24.5 \text{ m}

Step 2: Find the Area (AA). A=πr2A = \pi r^2 A=227×492×492A = \frac{22}{7} \times \frac{49}{2} \times \frac{49}{2} A=11×7×492A = \frac{11 \times 7 \times 49}{2} A=37732=1886.5 m2A = \frac{3773}{2} = 1886.5 \text{ m}^2

Explanation:

First, we use the circumference formula to isolate and solve for rr. Once the radius is found, we plug it into the area formula to calculate the total surface area of the sheet.