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Perimeter and Area - Area of a Triangle

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A triangle is a three-sided polygon, and its area represents the total region enclosed within its three boundaries. To calculate this area, we look at the relationship between its base and its corresponding altitude (height).

Any side of a triangle can be considered as the base. The height, or altitude, is the perpendicular line segment drawn from the opposite vertex to the base. Visually, imagine a triangle sitting on a horizontal line (the base); the height is the straight vertical distance from the highest point (vertex) down to that line, forming a 9090^{\circ} angle.

The area of a triangle is exactly half the area of a parallelogram that has the same base and height. If you take two identical triangles and flip one to join them along a side, they form a parallelogram, which is why the triangle formula includes a factor of 12\frac{1}{2}.

In a right-angled triangle, the two sides that meet at the 9090^{\circ} angle (the legs) can be used as the base and the height. Visually, this looks like half of a rectangle divided by a diagonal line.

For an obtuse-angled triangle, the height might fall outside the triangle. To visualize this, you must extend the base line with a dotted line and drop a perpendicular from the top vertex to meet this extended line outside the triangle's body.

The unit for area is always in square units, such as cm2cm^{2}, m2m^{2}, or mm2mm^{2}. This is because area involves the product of two linear dimensions (base and height).

Triangles that share the same base and are located between the same pair of parallel lines will have the same area because their heights remain constant, even if the triangles have different shapes or 'slants'.

📐Formulae

Area of a triangle = 12×base×height\frac{1}{2} \times \text{base} \times \text{height}

A=12×b×hA = \frac{1}{2} \times b \times h

Base of a triangle = 2×Areaheight\frac{2 \times \text{Area}}{\text{height}}

Height of a triangle = 2×Areabase\frac{2 \times \text{Area}}{\text{base}}

💡Examples

Problem 1:

Find the area of a triangle whose base is 12 cm12\ cm and whose corresponding height is 7 cm7\ cm.

Solution:

  1. Identify the given values: base b=12 cmb = 12\ cm and height h=7 cmh = 7\ cm.\n2. Apply the formula: Area=12×b×hArea = \frac{1}{2} \times b \times h\n3. Substitute the values: Area=12×12×7Area = \frac{1}{2} \times 12 \times 7\n4. Calculate: Area=6×7=42 cm2Area = 6 \times 7 = 42\ cm^{2}.\nTherefore, the area of the triangle is 42 cm242\ cm^{2}.

Explanation:

To find the area, we simply multiply the base by the height and then divide by 22. Since both measurements are in cmcm, the final result is in cm2cm^{2}.

Problem 2:

The area of a triangle is 36 cm236\ cm^{2}. If its height is 9 cm9\ cm, find the length of its base.

Solution:

  1. Identify the given values: Area=36 cm2Area = 36\ cm^{2} and h=9 cmh = 9\ cm.\n2. Use the modified formula for base: b=2×Areahb = \frac{2 \times Area}{h}\n3. Substitute the values: b=2×369b = \frac{2 \times 36}{9}\n4. Calculate: b=729=8 cmb = \frac{72}{9} = 8\ cm.\nTherefore, the base of the triangle is 8 cm8\ cm.

Explanation:

When the area and height are known, we can rearrange the area formula to solve for the base. Multiplying the area by 22 and dividing by the height gives the required base length.