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Perimeter and Area - Area of a Parallelogram

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A parallelogram is a four-sided flat shape (quadrilateral) where the opposite sides are parallel and equal in length. Visually, it looks like a rectangle that has been tilted or 'pushed' to one side.

The 'Base' (bb) of a parallelogram can be any of its four sides. In diagrams, it is usually the side shown at the bottom, represented by a solid horizontal line.

The 'Height' (hh) is the perpendicular distance from the base to the opposite parallel side. Visually, this is often represented by a dashed vertical line dropped from a top vertex to the base (or an extension of the base), forming a 9090^{\circ} angle marked with a small square symbol.

The area of a parallelogram is the region enclosed within its four sides. If you visually cut a triangle from one side of the parallelogram and slide it to the other side, the shape transforms into a rectangle. This shows that the area of a parallelogram is identical to the area of a rectangle with the same base and height.

It is crucial to use the 'corresponding height' for a specific base. If a parallelogram has two different pairs of parallel sides, each pair has its own specific perpendicular distance (height) between them.

Area is always expressed in square units, such as cm2cm^{2} or m2m^{2}, representing how many small unit squares would fit inside the shape.

A single diagonal divides a parallelogram into two congruent triangles of equal area. Consequently, the area of each triangle is exactly 12\frac{1}{2} the area of the parallelogram: Area of Triangle=12×b×h\text{Area of Triangle} = \frac{1}{2} \times b \times h.

📐Formulae

Area of a Parallelogram=b×h\text{Area of a Parallelogram} = b \times h

Base (b)=AreaHeight\text{Base (b)} = \frac{\text{Area}}{\text{Height}} strength

Height (h)=AreaBase\text{Height (h)} = \frac{\text{Area}}{\text{Base}}

💡Examples

Problem 1:

Find the area of a parallelogram whose base is 12 cm12\text{ cm} and corresponding height is 7 cm7\text{ cm}.

Solution:

Given:\nBase (bb) = 12 cm12\text{ cm}\nHeight (hh) = 7 cm7\text{ cm}\n\nUsing the formula:\nArea=b×h\text{Area} = b \times h\nArea=12 cm×7 cm\text{Area} = 12\text{ cm} \times 7\text{ cm}\nArea=84 cm2\text{Area} = 84\text{ cm}^{2}

Explanation:

To find the area, we simply identify the base and the perpendicular height from the problem and multiply them together. Ensure the units are square centimeters.

Problem 2:

The area of a parallelogram is 48 cm248\text{ cm}^{2} and its height is 6 cm6\text{ cm}. Find the length of its base.

Solution:

Given:\nArea = 48 cm248\text{ cm}^{2}\nHeight (hh) = 6 cm6\text{ cm}\n\nUsing the formula for base:\nBase (b)=AreaHeight\text{Base (b)} = \frac{\text{Area}}{\text{Height}}\nBase (b)=486\text{Base (b)} = \frac{48}{6}\nBase (b)=8 cm\text{Base (b)} = 8\text{ cm}

Explanation:

When the area and height are known, we can find the missing base by dividing the total area by the given height.