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Integers - Properties of Addition and Subtraction of Integers

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Closure Property of Addition: For any two integers aa and bb, their sum a+ba + b is always an integer. Visually, if you pick any two marked points on an infinite number line and add their values, the result will always land exactly on another marked integer point, never in the gaps between them.

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Closure Property of Subtraction: For any two integers aa and bb, the result of aβˆ’ba - b is always an integer. This ensures that the set of integers is complete under the operation of subtraction, meaning you can subtract any integer from another and stay within the same number system.

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Commutative Property of Addition: The sum of two integers remains the same regardless of the order in which they are added, expressed as a+b=b+aa + b = b + a. Imagine two physical stacks of weights; whether you place a 2kg2kg weight on top of a 5kg5kg weight or vice versa, the total pressure on the scale remains exactly the same.

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Associative Property of Addition: When three or more integers are added, the result is the same regardless of how the numbers are grouped, shown as (a+b)+c=a+(b+c)(a + b) + c = a + (b + c). Visually, if you have three groups of dots, you will get the same total count whether you combine the first two groups first and then the third, or combine the last two first and then add the first.

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Additive Identity: The integer 00 is called the additive identity because adding 00 to any integer aa results in the same integer aa, such that a+0=aa + 0 = a. On a number line, adding zero represents a 'zero-length' jump, meaning you remain at your original coordinate without moving left or right.

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Non-commutativity of Subtraction: Subtraction does not follow the commutative property, meaning aβˆ’bβ‰ bβˆ’aa - b \neq b - a for any distinct integers aa and bb. Visually, taking 3 steps forward and 5 steps back puts you at a different final location than taking 5 steps forward and 3 steps back.

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Non-associativity of Subtraction: The way integers are grouped in subtraction changes the final result, so (aβˆ’b)βˆ’cβ‰ aβˆ’(bβˆ’c)(a - b) - c \neq a - (b - c). This means the parentheses are crucial in subtraction problems to define which operation happens first.

πŸ“Formulae

a+b=c (where c∈Z)a + b = c \text{ (where } c \in \mathbb{Z})

aβˆ’b=cΒ (whereΒ c∈Z)a - b = c \text{ (where } c \in \mathbb{Z})

a+b=b+aa + b = b + a

(a+b)+c=a+(b+c)(a + b) + c = a + (b + c)

a+0=a=0+aa + 0 = a = 0 + a

aβˆ’bβ‰ bβˆ’aΒ (ifΒ aβ‰ b)a - b \neq b - a \text{ (if } a \neq b)

(aβˆ’b)βˆ’cβ‰ aβˆ’(bβˆ’c)(a - b) - c \neq a - (b - c)

πŸ’‘Examples

Problem 1:

Verify the Associative Property of Addition for the integers a=βˆ’5a = -5, b=3b = 3, and c=βˆ’2c = -2.

Solution:

Step 1: Calculate the Left Hand Side (LHS) using the grouping (a+b)+c(a + b) + c: ((βˆ’5)+3)+(βˆ’2)=(βˆ’2)+(βˆ’2)=βˆ’4((-5) + 3) + (-2) = (-2) + (-2) = -4. Step 2: Calculate the Right Hand Side (RHS) using the grouping a+(b+c)a + (b + c): (βˆ’5)+(3+(βˆ’2))=(βˆ’5)+(1)=βˆ’4(-5) + (3 + (-2)) = (-5) + (1) = -4. Step 3: Compare LHS and RHS. Since βˆ’4=βˆ’4-4 = -4, the property is verified.

Explanation:

This example demonstrates that the sum of integers does not depend on how they are grouped together using parentheses.

Problem 2:

Show that subtraction is not commutative for integers a=8a = 8 and b=βˆ’3b = -3.

Solution:

Step 1: Calculate aβˆ’ba - b: 8βˆ’(βˆ’3)=8+3=118 - (-3) = 8 + 3 = 11. Step 2: Calculate bβˆ’ab - a: (βˆ’3)βˆ’8=βˆ’11(-3) - 8 = -11. Step 3: Compare the results. Since 11β‰ βˆ’1111 \neq -11, we have shown aβˆ’bβ‰ bβˆ’aa - b \neq b - a.

Explanation:

This step-by-step calculation proves that changing the order of numbers in a subtraction expression results in different values (in this case, additive opposites).