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Integers - Division of Integers and its Properties

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Division as Inverse Operation: Division is the mathematical inverse of multiplication. For every multiplication statement for non-zero integers, there are two related division statements. For example, if 2×(3)=62 \times (-3) = -6, then (6)÷(3)=2(-6) \div (-3) = 2 and (6)÷2=3(-6) \div 2 = -3.

Division of Integers with Like Signs: When a positive integer is divided by a positive integer, or a negative integer is divided by a negative integer, the quotient is always a positive integer. Conceptually, if you think of a number line, dividing a total negative distance into groups of negative steps results in a positive number of groups.

Division of Integers with Different Signs: When a positive integer is divided by a negative integer, or a negative integer is divided by a positive integer, the quotient is always a negative integer. This can be visualized as taking a negative total and dividing it into equal positive parts, which naturally stay on the negative side of the number line.

Division by Zero and One: Any integer aa divided by 11 gives the same integer aa. However, division of any integer by zero is undefined because it is impossible to divide a quantity into zero parts. Conversely, zero divided by any non-zero integer aa is always 00.

Properties of Division (Closure and Commutative): Unlike addition and multiplication, division of integers does not satisfy the closure property because the quotient of two integers may not always be an integer (e.g., 5÷2=2.55 \div 2 = 2.5). It is also not commutative, meaning the order of numbers matters: a÷ba \div b is not equal to b÷ab \div a.

Associative Property of Division: The associative property does not hold for the division of integers. This means that for any three integers aa, bb, and cc, the grouping of terms changes the result: (a÷b)÷ca÷(b÷c)(a \div b) \div c \neq a \div (b \div c). If you visualize this as nested operations, changing the 'inner' group changes the scale of the final division.

📐Formulae

a÷(b)=(a)÷b=(ab)a \div (-b) = (-a) \div b = -\left(\frac{a}{b}\right), where b0b \neq 0

(a)÷(b)=ab(-a) \div (-b) = \frac{a}{b}, where b0b \neq 0

a÷1=aa \div 1 = a

a÷(1)=aa \div (-1) = -a

0÷a=00 \div a = 0, where a0a \neq 0

a÷0a \div 0 is undefined

(a+b)÷c=(a÷c)+(b÷c)(a + b) \div c = (a \div c) + (b \div c) (Only if aa and bb are perfectly divisible by cc)

💡Examples

Problem 1:

Evaluate: [(48)÷12]÷(2)[(-48) \div 12] \div (-2)

Solution:

Step 1: Solve the expression inside the square brackets first. Divide 48-48 by 1212. Since the signs are different, the quotient is negative: (48)÷12=4(-48) \div 12 = -4. \nStep 2: Now divide the result by the remaining integer: (4)÷(2)(-4) \div (-2). \nStep 3: Since both integers are negative (like signs), the quotient is positive: 4÷2=24 \div 2 = 2. \nFinal Answer: 22

Explanation:

The problem is solved using the BODMAS rule, prioritizing the brackets first and then applying the sign rules for division.

Problem 2:

Find the value of xx in the equation: x÷(5)=25x \div (-5) = 25

Solution:

Step 1: To find xx, use the concept of division as the inverse of multiplication. Multiply both sides by 5-5. \nStep 2: x=25×(5)x = 25 \times (-5). \nStep 3: Multiply the numbers: 25×5=12525 \times 5 = 125. \nStep 4: Determine the sign. A positive number multiplied by a negative number results in a negative product. \nStep 5: Therefore, x=125x = -125.

Explanation:

This approach uses the inverse operation property, where moving a divisor to the other side of the equation turns it into a multiplier.