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Algebraic Expressions - Addition and Subtraction of Algebraic Expressions

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Algebraic expressions are formed by combining variables and constants using arithmetic operations like addition and subtraction. Visually, think of an expression like 3x+53x + 5 as a combination of three unknown 'boxes' (xx) and five fixed 'units' (55).

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Terms are the individual parts of an expression separated by ++ or βˆ’- signs. For example, in 5x2βˆ’3xy5x^2 - 3xy, the terms are 5x25x^2 and βˆ’3xy-3xy. You can visualize this as a tree structure where the expression is the trunk and each term is a major branch.

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A factor is a multiplier within a term. In the term 4xy4xy, the factors are 4,x,Β andΒ y4, x, \text{ and } y. The numerical factor is called the coefficient. For example, in βˆ’7ab-7ab, the coefficient is βˆ’7-7. Visualizing a term as a product box helps identify these components.

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Like terms are terms that contain the same variables raised to the same powers, regardless of their numerical coefficients. For example, 2x2y2x^2y and βˆ’5x2y-5x^2y are like terms. Unlike terms have different variables or powers, such as 3x3x and 3x23x^2. Addition and subtraction can only be performed on like terms.

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To add algebraic expressions, we identify and group the like terms together, then add their numerical coefficients. Visually, this is like sorting different types of fruit; you can add 3 apples to 2 apples to get 5 apples, but you cannot combine apples and oranges into a single unit.

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To subtract one expression from another, we add the additive inverse of the expression being subtracted. This means changing the sign of every term in the expression that follows the minus sign (from ++ to βˆ’- and from βˆ’- to ++).

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There are two main layouts for performing these operations: the Horizontal Method, where terms are grouped side-by-side in a single line, and the Column Method, where expressions are written one below the other with like terms aligned in vertical columns for easy calculation.

πŸ“Formulae

ax+bx=(a+b)xax + bx = (a + b)x

axβˆ’bx=(aβˆ’b)xax - bx = (a - b)x

Terms=CoefficientΓ—AlgebraicΒ FactorsTerms = \text{Coefficient} \times \text{Algebraic Factors}

βˆ’(a+b)=βˆ’aβˆ’b-(a + b) = -a - b

βˆ’(aβˆ’b)=βˆ’a+b-(a - b) = -a + b

a+(b+c)=(a+b)+ca + (b + c) = (a + b) + c

πŸ’‘Examples

Problem 1:

Add the algebraic expressions: 5x2+7xβˆ’35x^2 + 7x - 3 and 2x2βˆ’4x+82x^2 - 4x + 8.

Solution:

Step 1: Write the expressions together: (5x2+7xβˆ’3)+(2x2βˆ’4x+8)(5x^2 + 7x - 3) + (2x^2 - 4x + 8) \ Step 2: Group the like terms: (5x2+2x2)+(7xβˆ’4x)+(βˆ’3+8)(5x^2 + 2x^2) + (7x - 4x) + (-3 + 8) \ Step 3: Add the coefficients of the like terms: (5+2)x2+(7βˆ’4)x+5(5+2)x^2 + (7-4)x + 5 \ Result: 7x2+3x+57x^2 + 3x + 5

Explanation:

In this problem, we identify three sets of like terms: x2x^2 terms, xx terms, and constant terms. We then perform simple addition or subtraction on their coefficients while keeping the variable parts the same.

Problem 2:

Subtract 3abβˆ’2a+5b3ab - 2a + 5b from 7ab+5aβˆ’2b7ab + 5a - 2b.

Solution:

Step 1: Set up the subtraction: (7ab+5aβˆ’2b)βˆ’(3abβˆ’2a+5b)(7ab + 5a - 2b) - (3ab - 2a + 5b) \ Step 2: Change the signs of all terms in the second expression: 7ab+5aβˆ’2bβˆ’3ab+2aβˆ’5b7ab + 5a - 2b - 3ab + 2a - 5b \ Step 3: Group the like terms together: (7abβˆ’3ab)+(5a+2a)+(βˆ’2bβˆ’5b)(7ab - 3ab) + (5a + 2a) + (-2b - 5b) \ Step 4: Simplify: 4ab+7aβˆ’7b4ab + 7a - 7b

Explanation:

Subtracting an expression requires changing the signs of the 'subtrahend' (the part being taken away). After distributing the negative sign, we simply combine the like terms for abab, aa, and bb respectively.