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Ratio and Proportion - Unitary Method

Grade 6ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Definition of Ratio: A ratio is a comparison of two quantities of the same kind and in the same units by division, expressed as a:ba:b or ab\frac{a}{b}. Visually, imagine two line segments where one is twice as long as the other; the ratio of their lengths is 2:12:1, regardless of whether they are measured in cm or inches.

Simplest Form of Ratio: A ratio is in its simplest form when the antecedent (first term) and the consequent (second term) have no common factor other than 11. Visualize a large rectangle divided into 1212 small squares with 44 colored red; the ratio 4:124:12 can be simplified to 1:31:3, meaning for every 11 red square, there are 33 total squares.

Concept of Proportion: An equality of two ratios is called a proportion, written as a:b=c:da:b = c:d or a:b::c:da:b :: c:d. Imagine a photograph being enlarged; to keep the image from looking distorted, the ratio of height to width in the original must equal the ratio of height to width in the enlargement.

Terms of Proportion: In the proportion a:b::c:da:b :: c:d, aa and dd are called the 'extremes' while bb and cc are called the 'means'. A helpful visual is to see them as a chain where the outer links are the extremes and the inner links are the means, and for the proportion to hold, the product of the outer links must equal the product of the inner links.

The Unitary Method: This is a technique used to solve problems by first finding the value of a single unit and then finding the necessary value by multiplying the single unit value. Think of a carton containing 1212 eggs; to find the cost of 55 eggs, you first 'zoom in' to find the price of just 11 egg.

Finding Value of One Unit: To find the value of one unit, we use division. The rule is: Value of one unit=Total valueTotal quantity\text{Value of one unit} = \frac{\text{Total value}}{\text{Total quantity}}. Visualize sharing 2020 candies equally among 55 children to determine how many candies 11 child receives.

Finding Value of Multiple Units: Once the value of 11 unit is known, we use multiplication to find the value of the required number of units. Value of nextunits=Value of 1extunit×n\text{Value of } n ext{ units} = \text{Value of } 1 ext{ unit} \times n. Imagine knowing the weight of 11 brick and stacking 1010 of them to find the total weight.

Direct Variation: In standard unitary method problems for Grade 6, quantities usually increase or decrease together. This can be visualized as a straight-line graph passing through the origin (0,0)(0,0); if you buy 00 items, you pay 00 amount, and as you move right on the quantity axis, the cost axis goes up at a steady rate.

📐Formulae

a:b=aba:b = \frac{a}{b}

a:b::c:dab=cda:b :: c:d \Rightarrow \frac{a}{b} = \frac{c}{d}

Product of Extremes=Product of Meansa×d=bimesc\text{Product of Extremes} = \text{Product of Means} \Rightarrow a \times d = b imes c

Value of 1extunit=extTotalValueextTotalQuantity\text{Value of } 1 ext{ unit} = \frac{ ext{Total Value}}{ ext{Total Quantity}}

Value of required units=(Value of 1extunit)×Required Quantity\text{Value of required units} = (\text{Value of } 1 ext{ unit}) \times \text{Required Quantity}

💡Examples

Problem 1:

The cost of 1515 identical notebooks is 675675 rupees. Find the cost of 77 such notebooks.

Solution:

Step 1: Find the cost of 11 notebook. Cost of 1515 notebooks = 675675 rupees Cost of 11 notebook = 67515\frac{675}{15} Cost of 11 notebook = 4545 rupees

Step 2: Find the cost of 77 notebooks. Cost of 77 notebooks = 45×745 \times 7 Cost of 77 notebooks = 315315 rupees

Explanation:

We use the unitary method by first dividing the total cost by the number of notebooks to find the 'unit price'. Then, we multiply this unit price by the desired quantity (77).

Problem 2:

A car travels 180 km180 \text{ km} in 4 hours4 \text{ hours} at a constant speed. How far will it travel in 7 hours7 \text{ hours}?

Solution:

Step 1: Find the distance traveled in 1 hour1 \text{ hour}. Distance in 4 hours=180 km4 \text{ hours} = 180 \text{ km} Distance in 1 hour=1804=45 km1 \text{ hour} = \frac{180}{4} = 45 \text{ km}

Step 2: Find the distance traveled in 7 hours7 \text{ hours}. Distance in 7 hours=45×7=315 km7 \text{ hours} = 45 \times 7 = 315 \text{ km}

Explanation:

First, calculate the speed (distance per 11 unit of time) by dividing 180180 by 44. Once the distance for 11 hour is found, multiply it by 77 to find the total distance for the longer duration.