krit.club logo

Shape and Space - Properties and Classification of Triangles

Grade 6IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A triangle is a two-dimensional polygon with three sides, three vertices, and three interior angles. Visually, it is the simplest closed shape made of straight line segments.

The Interior Angle Sum Theorem states that the sum of the three interior angles in any triangle is always 180180^\circ. Imagine tearing the three corners of any paper triangle and placing them side-by-side; they will form a perfect straight line.

Triangles are classified by their side lengths: an Equilateral triangle has three equal sides and three 6060^\circ angles; an Isosceles triangle has at least two equal sides and two equal base angles; and a Scalene triangle has no equal sides or angles.

Triangles are also classified by their internal angles: an Acute triangle has three angles less than 9090^\circ; a Right-angled triangle has exactly one 9090^\circ angle (often marked with a small square in the corner); and an Obtuse triangle has one angle greater than 9090^\circ.

The Triangle Inequality Theorem dictates that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side (a+b>ca + b > c). Visually, if one side is too long relative to the others, the two shorter sides will not be able to connect to form a closed shape.

The height (altitude) of a triangle is the perpendicular distance from a vertex to the opposite side, which acts as the base. In a right-angled triangle, the two sides forming the 9090^\circ angle can serve as the base and height. In an obtuse triangle, the height might fall outside the triangle's body.

The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the two opposite interior angles. If you extend one side of a triangle outward, the angle formed between the extension and the adjacent side is the exterior angle.

📐Formulae

Sum of interior angles: A+B+C=180A + B + C = 180^\circ

Area of a triangle: Area=12×base×heightArea = \frac{1}{2} \times \text{base} \times \text{height}

Perimeter of a triangle: P=a+b+cP = a + b + c

Triangle Inequality: a+b>ca + b > c, a+c>ba + c > b, and b+c>ab + c > a

💡Examples

Problem 1:

In an isosceles triangle, the vertex angle (the angle between the two equal sides) measures 7070^\circ. Calculate the size of the two remaining base angles.

Solution:

Step 1: Let the two equal base angles be represented by xx. Step 2: Since the sum of angles is 180180^\circ, the equation is x+x+70=180x + x + 70^\circ = 180^\circ. Step 3: Simplify to 2x+70=1802x + 70^\circ = 180^\circ. Step 4: Subtract 7070^\circ from both sides: 2x=1102x = 110^\circ. Step 5: Divide by 22: x=55x = 55^\circ.

Explanation:

This solution uses the property that an isosceles triangle has two equal angles and the fact that the total interior sum must be 180180^\circ.

Problem 2:

Find the area of a triangle where the base is 12 cm12\text{ cm} and the perpendicular height is 7 cm7\text{ cm}.

Solution:

Step 1: Identify the values: base(b)=12\text{base} (b) = 12 and height(h)=7\text{height} (h) = 7. Step 2: Use the area formula A=12×b×hA = \frac{1}{2} \times b \times h. Step 3: Substitute the values: A=12×12×7A = \frac{1}{2} \times 12 \times 7. Step 4: Calculate A=6×7=42A = 6 \times 7 = 42. Final Answer: 42 cm242\text{ cm}^2.

Explanation:

The area is calculated by taking half of the product of the base and the vertical height that is perpendicular to that base.