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Patterns and Algebra - The Cartesian Coordinate Plane (Four Quadrants)

Grade 6IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Cartesian Plane is a two-dimensional grid formed by the intersection of two perpendicular number lines: the horizontal x-axis and the vertical y-axis. They meet at a central point called the origin, which is labeled (0,0)(0, 0). This grid allows us to locate any point in space using a set of coordinates.

An Ordered Pair (x,y)(x, y) specifies the exact position of a point. The first value, the x-coordinate, represents the horizontal distance from the origin (move right for positive values, left for negative values). The second value, the y-coordinate, represents the vertical distance (move up for positive values, down for negative values).

The intersection of the axes divides the plane into four distinct regions called Quadrants, numbered I to IV in a counter-clockwise direction starting from the top-right. Quadrant I (top-right) contains points with signs (+,+)(+, +), Quadrant II (top-left) contains (,+)(-, +), Quadrant III (bottom-left) contains (,)(-, -), and Quadrant IV (bottom-right) contains (+,)(+, -). Visually, this creates a cross shape with the origin at the center.

To plot a point such as (2,3)(-2, 3), you begin at the origin (0,0)(0, 0). First, move 22 units to the left along the x-axis because the x-coordinate is negative. Then, move 33 units vertically up because the y-coordinate is positive. Mark the point where these two paths meet.

Points located directly on the axes always have at least one coordinate equal to zero. If a point is on the x-axis, its y-coordinate is zero, such as (5,0)(5, 0). If a point is on the y-axis, its x-coordinate is zero, such as (0,4)(0, -4). These points do not belong to any specific quadrant but lie on the boundary between them.

Reflections are transformations where a point is 'flipped' over an axis. When reflecting point (x,y)(x, y) across the x-axis, the x-coordinate stays the same but the y-coordinate changes sign, resulting in (x,y)(x, -y). When reflecting across the y-axis, the y-coordinate stays the same but the x-coordinate changes sign, resulting in (x,y)(-x, y). This creates a mirror image across the chosen axis line.

Horizontal and Vertical distance can be calculated by finding the absolute difference between coordinates. If two points have the same y-coordinate, the distance between them is the absolute difference of their x-coordinates. If they have the same x-coordinate, the distance is the absolute difference of their y-coordinates.

📐Formulae

extOrderedPair=(x,y) ext{Ordered Pair} = (x, y)

extOrigin=(0,0) ext{Origin} = (0, 0)

extHorizontalDistance=x2x1 ext{Horizontal Distance} = |x_2 - x_1| (when yy values are equal)

extVerticalDistance=y2y1 ext{Vertical Distance} = |y_2 - y_1| (when xx values are equal)

extReflectionacrossxaxisof(x,y)ightarrow(x,y) ext{Reflection across x-axis of } (x, y) ightarrow (x, -y)

extReflectionacrossyaxisof(x,y)ightarrow(x,y) ext{Reflection across y-axis of } (x, y) ightarrow (-x, y)

💡Examples

Problem 1:

Determine the coordinates and the quadrant for a point AA that is located 55 units to the left of the y-axis and 22 units above the x-axis.

Solution:

Step 1: Identify the x-coordinate. '5 units to the left' corresponds to an x-value of 5-5. \ Step 2: Identify the y-coordinate. '2 units above' corresponds to a y-value of +2+2. \ Step 3: Combine them into an ordered pair: (5,2)(-5, 2). \ Step 4: Determine the quadrant. Since the x-coordinate is negative and the y-coordinate is positive (,+)(-, +), the point lies in Quadrant II.

Explanation:

We use the directional descriptions to assign signs to the coordinates and then apply the quadrant rules based on those signs.

Problem 2:

Find the distance between point M(3,4)M(-3, 4) and point N(5,4)N(5, 4).

Solution:

Step 1: Observe the coordinates. Both points have the same y-coordinate, which is 44. This means the points lie on a horizontal line. \ Step 2: Use the horizontal distance formula: x2x1|x_2 - x_1|. \ Step 3: Substitute the values: 5(3)|5 - (-3)|. \ Step 4: Calculate the absolute difference: 5+3=8=8|5 + 3| = |8| = 8. \ The distance is 88 units.

Explanation:

Because the vertical position is identical, we only need to find how many units apart the points are along the horizontal x-axis.