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Measurement - Circumference and Area of Circles

Grade 6IB

Review the key concepts, formulae, and examples before starting your quiz.

๐Ÿ”‘Concepts

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The Radius (rr) is a straight line segment from the center of the circle to any point on its boundary. The Diameter (dd) is a straight line passing through the center to connect two points on opposite sides of the boundary. Visually, the diameter is exactly twice the length of the radius, expressed as d=2rd = 2r.

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Circumference is the total distance around the edge of the circle, functioning exactly like the perimeter of a polygon. If you were to 'unroll' the circle's boundary into a straight line, the length of that line would be the circumference.

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The constant ฯ€\pi (Pi) is an irrational number approximately equal to 3.143.14 or 227\frac{22}{7}. It represents the fixed ratio between a circle's circumference and its diameter (Cรทd=ฯ€C \div d = \pi). Regardless of the circle's size, this ratio remains constant.

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The Area of a circle is the total surface space enclosed within its boundary. While circumference measures length in linear units (like cmcm), area measures the 'flat' space inside in square units (like cm2cm^2).

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To visualize the Area formula (A=ฯ€r2A = \pi r^2), imagine a square with side length equal to the radius (rr). The area of this 'radius square' is r2r^2. The circle's total area is slightly more than 33 (specifically ฯ€\pi) of these squares.

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A Semicircle is exactly half of a circle, created by cutting the circle along its diameter. Its curved boundary is half of the total circumference, but its total perimeter must also include the straight diameter line.

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A Quadrant is one-fourth of a circle. Its area is calculated as 14ฯ€r2\frac{1}{4} \pi r^2. Visually, it looks like a slice of pie with two straight edges (radii) meeting at a 90โˆ˜90^{\circ} angle at the center.

๐Ÿ“Formulae

d=2rd = 2r

r=d2r = \frac{d}{2}

C=ฯ€dC = \pi d

C=2ฯ€rC = 2 \pi r

A=ฯ€r2A = \pi r^2

ฯ€โ‰ˆ3.14\pi \approx 3.14 or 227\frac{22}{7}

๐Ÿ’กExamples

Problem 1:

A circular clock has a radius of 7cm7 cm. Calculate its circumference. (Use ฯ€=227\pi = \frac{22}{7})

Solution:

  1. Identify the given value: r=7cmr = 7 cm.
  2. Choose the circumference formula involving radius: C=2ฯ€rC = 2 \pi r.
  3. Substitute the values: C=2ร—227ร—7C = 2 \times \frac{22}{7} \times 7.
  4. Simplify: The 77 in the numerator and denominator cancel out, leaving C=2ร—22C = 2 \times 22.
  5. Calculate the final value: C=44cmC = 44 cm.

Explanation:

Since the radius is a multiple of 77, using the fraction 227\frac{22}{7} for ฯ€\pi makes the calculation easier through cancellation.

Problem 2:

A circular garden has a diameter of 10m10 m. Find the total area of the garden. (Use ฯ€=3.14\pi = 3.14)

Solution:

  1. Identify the given value: d=10md = 10 m.
  2. Find the radius (rr): r=d2=102=5mr = \frac{d}{2} = \frac{10}{2} = 5 m.
  3. Use the area formula: A=ฯ€r2A = \pi r^2.
  4. Substitute the values: A=3.14ร—(5)2A = 3.14 \times (5)^2.
  5. Calculate the square: 52=255^2 = 25.
  6. Multiply: A=3.14ร—25=78.5m2A = 3.14 \times 25 = 78.5 m^2.

Explanation:

Always convert diameter to radius first before calculating area, as the area formula requires r2r^2 rather than d2d^2.