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Understanding Elementary Shapes - Measuring Line Segments

Grade 6CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A line segment is a fixed portion of a line that has two distinct endpoints. It is typically represented as AB\overline{AB}, showing a straight path connecting point AA and point BB.

Comparison by observation involves looking at two line segments to decide which is longer. While simple, this method is often inaccurate, especially when the difference in length is very small, such as two segments appearing nearly identical to the naked eye.

Comparison by tracing involves using tracing paper to copy one segment and placing it over another. The accuracy of this method depends entirely on how precisely the segment is traced and then compared visually.

Measurement using a ruler is the most common method. A standard ruler is divided into 1515 centimeters (cmcm), where each centimeter is further divided into 1010 smaller parts called millimeters (mmmm). A segment's length is determined by placing the 00 mark at one end and reading the value at the other end.

The divider is a tool with two metal points used for more accurate measurements. By placing the points of the divider on the endpoints of a line segment and then lifting it to place it on a ruler, we avoid errors caused by the thickness of the ruler.

Parallax error occurs when the eye is not positioned vertically above the mark being read on the ruler. To avoid this, the eye must be placed directly over the point of measurement to ensure the reading is exact.

A point CC is said to lie between points AA and BB only if A,B,A, B, and CC are collinear (on the same line) and the sum of the lengths of the smaller segments equals the total length, expressed as AC+CB=ABAC + CB = AB.

The midpoint of a line segment is a point that divides the segment into two equal halves. Visually, if MM is the midpoint of AB\overline{AB}, then the distance from AA to MM is the same as the distance from MM to BB.

📐Formulae

1 cm=10 mm1 \text{ cm} = 10 \text{ mm}

1 mm=0.1 cm1 \text{ mm} = 0.1 \text{ cm}

If C is between A and B, then AB=AC+CB\text{If } C \text{ is between } A \text{ and } B, \text{ then } AB = AC + CB

If M is the midpoint of AB, then AM=MB=12AB\text{If } M \text{ is the midpoint of } \overline{AB}, \text{ then } AM = MB = \frac{1}{2} AB

💡Examples

Problem 1:

If A,B,CA, B, C are three points on a line such that AB=5 cmAB = 5 \text{ cm}, BC=3 cmBC = 3 \text{ cm} and AC=8 cmAC = 8 \text{ cm}, which point lies between the other two?

Solution:

Step 1: Identify the lengths given: AB=5 cmAB = 5 \text{ cm}, BC=3 cmBC = 3 \text{ cm}, and AC=8 cmAC = 8 \text{ cm}.\nStep 2: Check the sum of the shorter segments: AB+BC=5 cm+3 cm=8 cmAB + BC = 5 \text{ cm} + 3 \text{ cm} = 8 \text{ cm}.\nStep 3: Since AB+BC=ACAB + BC = AC, it satisfies the condition for collinearity where BB is the common point.

Explanation:

In any line segment where AC=AB+BCAC = AB + BC, the point BB must lie between AA and CC because the total distance is the sum of the two parts.

Problem 2:

Verify whether DD is the midpoint of AG\overline{AG} if the coordinates of points on a number line are A(1),B(2),C(3),D(4),E(5),F(6),G(7)A(1), B(2), C(3), D(4), E(5), F(6), G(7).

Solution:

Step 1: Calculate the distance ADAD. AD=41=3 unitsAD = 4 - 1 = 3 \text{ units}.\nStep 2: Calculate the distance DGDG. DG=74=3 unitsDG = 7 - 4 = 3 \text{ units}.\nStep 3: Compare the distances. Since AD=DG=3 unitsAD = DG = 3 \text{ units}, DD is equidistant from AA and GG.

Explanation:

A point is a midpoint if it is exactly in the middle of the segment, meaning the distance from the start point to the midpoint is equal to the distance from the midpoint to the end point.