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Playing with Numbers - Common Factors and Common Multiples

Grade 6CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Factors and Multiples: A factor of a number is an exact divisor that leaves no remainder. Visualize factors as all possible rectangular arrangements of a set of items; for instance, 1212 items can be arranged in 1×12,2×6,1 \times 12, 2 \times 6, or 3×43 \times 4 grids. A multiple is a number obtained by multiplying a given number by any whole number, which can be visualized as equal-sized jumps along a number line.

Common Factors: When two or more numbers have the same factors, those shared values are called common factors. If you represent the factors of two numbers using a Venn Diagram (two overlapping circles), the common factors are the numbers listed in the intersection where the circles overlap.

Highest Common Factor (HCF): The HCF is the largest value among all common factors of two or more numbers. It is also known as the Greatest Common Divisor (GCD). Imagine you have two ribbons of different lengths; the HCF is the length of the longest possible piece you can cut so that both ribbons are divided into equal parts with no leftovers.

Common Multiples: These are numbers that are multiples of all the given numbers in a set. On a number line where you mark multiples of 44 in red and multiples of 66 in blue, the common multiples are the points where both red and blue marks appear (12,24,36,12, 24, 36, \dots).

Lowest Common Multiple (LCM): The LCM is the smallest non-zero common multiple of two or more numbers. Visualize two runners on a circular track; if one finishes a lap in 4040 seconds and another in 6060 seconds, the LCM (120120 seconds) is the first time they will both cross the starting line together again.

Co-prime Numbers: Two numbers are called co-prime if their only common factor is 11. For example, 88 and 1515 are co-prime because the factors of 88 are {1,2,4,8}\{1, 2, 4, 8\} and the factors of 1515 are {1,3,5,15}\{1, 3, 5, 15\}. In a Venn diagram of their factors, the overlapping section would contain only the number 11.

Prime Factorization Method: This is a way to find HCF and LCM by breaking numbers down into products of prime numbers. For HCF, we multiply the common prime factors with the lowest powers. For LCM, we multiply all prime factors using their highest powers found in any of the numbers.

📐Formulae

Product of two numbers=HCF×LCM\text{Product of two numbers} = \text{HCF} \times \text{LCM}

HCF(a,b)=a×bLCM(a,b)\text{HCF}(a, b) = \frac{a \times b}{\text{LCM}(a, b)}

LCM(a,b)=a×bHCF(a,b)\text{LCM}(a, b) = \frac{a \times b}{\text{HCF}(a, b)}

Common FactorSmallest of the given numbers\text{Common Factor} \le \text{Smallest of the given numbers}

Common MultipleLargest of the given numbers\text{Common Multiple} \ge \text{Largest of the given numbers}

💡Examples

Problem 1:

Find the HCF and LCM of 1212 and 1818.

Solution:

Step 1: Find the factors of each number. Factors of 1212: 1,2,3,4,6,121, 2, 3, 4, 6, 12 Factors of 1818: 1,2,3,6,9,181, 2, 3, 6, 9, 18 Step 2: Identify common factors: 1,2,3,61, 2, 3, 6. The largest is 66, so HCF=6HCF = 6. Step 3: Find multiples of each number. Multiples of 1212: 12,24,36,48,60,12, 24, 36, 48, 60, \dots Multiples of 1818: 18,36,54,72,18, 36, 54, 72, \dots Step 4: Identify the smallest common multiple: 3636. So LCM=36LCM = 36.

Explanation:

This approach uses the listing method to identify shared factors and multiples directly. We can verify using the formula: 12×18=21612 \times 18 = 216 and HCF×LCM=6×36=216HCF \times LCM = 6 \times 36 = 216.

Problem 2:

Two bells toll at intervals of 99 minutes and 1212 minutes respectively. If they toll together at 10:0010:00 AM, at what time will they toll together again?

Solution:

Step 1: To find when they toll together, we need the Lowest Common Multiple (LCM) of 99 and 1212. Step 2: Prime factorization: 9=3×3=329 = 3 \times 3 = 3^{2} 12=2×2×3=22×312 = 2 \times 2 \times 3 = 2^{2} \times 3 Step 3: LCM is the product of highest powers of all prime factors: LCM=22×32=4×9=36LCM = 2^{2} \times 3^{2} = 4 \times 9 = 36. Step 4: The bells will toll together after 3636 minutes. Step 5: Add 3636 minutes to 10:0010:00 AM.

Explanation:

The problem asks for the next simultaneous event, which requires finding the LCM. Since the LCM is 3636, the bells will next toll together at 10:3610:36 AM.