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Knowing Our Numbers - Large Numbers in Practice

Grade 6CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Understanding Large Units: In practice, we use larger units to measure distance, mass, and capacity. For length, we use kilometers (kmkm), meters (mm), centimeters (cmcm), and millimeters (mmmm). Visualize a long highway measured in kmkm, while the thickness of a cardboard is measured in mmmm.

Units of Mass and Capacity: Mass is measured in kilograms (kgkg), grams (gg), and milligrams (mgmg). Capacity is measured in liters (LL) and milliliters (mLmL). Imagine a large sack of rice weighing 25 kg25 \text{ kg} versus a small medicine tablet weighing 250 mg250 \text{ mg}.

Unit Conversion Rules: To convert from a higher (larger) unit to a lower (smaller) unit, we multiply by the conversion factor. To convert from a lower unit to a higher unit, we divide. Think of a 'Conversion Staircase' where jumping down steps requires multiplication and climbing up requires division.

Estimation and Rounding: Estimation gives a rough idea of a quantity rather than an exact value. To round to the nearest ten, look at the ones digit: if it is 55 or more, round up; otherwise, round down. On a number line, the number 4848 is closer to 5050 than 4040, so it rounds to 5050.

Estimating Outcomes: We estimate the results of addition, subtraction, multiplication, and division by rounding numbers to their greatest place value. For example, estimating 5,290+17,9865,290 + 17,986 involves rounding both to the nearest thousand to get 5,000+18,000=23,0005,000 + 18,000 = 23,000.

Using Brackets: Brackets are used to simplify expressions and ensure the correct order of operations. For example, if you buy 55 pens at 1010 rupees each and 55 pencils at 22 rupees each, the total cost is 5×(10+2)5 \times (10 + 2), which simplifies the calculation by grouping the quantities.

Roman Numerals: This system uses seven basic symbols: I=1,V=5,X=10,L=50,C=100,D=500,M=1000I=1, V=5, X=10, L=50, C=100, D=500, M=1000. Rules include: symbols I,X,C,MI, X, C, M can be repeated up to three times, and if a smaller value symbol is placed before a larger one, it is subtracted (e.g., IV=51=4IV = 5 - 1 = 4).

📐Formulae

1 kilometer (km)=1000 meters (m)1 \text{ kilometer (km)} = 1000 \text{ meters (m)}

1 meter (m)=100 centimeters (cm)=1000 millimeters (mm)1 \text{ meter (m)} = 100 \text{ centimeters (cm)} = 1000 \text{ millimeters (mm)}

1 centimeter (cm)=10 millimeters (mm)1 \text{ centimeter (cm)} = 10 \text{ millimeters (mm)}

1 kilogram (kg)=1000 grams (g)1 \text{ kilogram (kg)} = 1000 \text{ grams (g)}

1 gram (g)=1000 milligrams (mg)1 \text{ gram (g)} = 1000 \text{ milligrams (mg)}

1 liter (L)=1000 milliliters (mL)1 \text{ liter (L)} = 1000 \text{ milliliters (mL)}

💡Examples

Problem 1:

A box contains 2,00,0002,00,000 medicine tablets each weighing 20 mg20 \text{ mg}. What is the total weight of all the tablets in the box in grams and in kilograms?

Solution:

Step 1: Find the total weight in mgmg. Total weight = 2,00,000×20 mg=40,00,000 mg2,00,000 \times 20 \text{ mg} = 40,00,000 \text{ mg}. Step 2: Convert mgmg to gg (1 g=1000 mg1 \text{ g} = 1000 \text{ mg}). Weight in gg = 40,00,0001000=4000 g\frac{40,00,000}{1000} = 4000 \text{ g}. Step 3: Convert gg to kgkg (1 kg=1000 g1 \text{ kg} = 1000 \text{ g}). Weight in kgkg = 40001000=4 kg\frac{4000}{1000} = 4 \text{ kg}.

Explanation:

We first calculate the total mass in the smallest unit provided, then progressively divide by 10001000 to reach grams and then kilograms.

Problem 2:

Estimate the product 5981×4425981 \times 442 by rounding off each number to its nearest hundreds.

Solution:

Step 1: Round 59815981 to the nearest hundred. Since the tens digit is 88 (greater than 55), we round up to 60006000 (or specifically to the nearest hundred, 60006000). Step 2: Round 442442 to the nearest hundred. Since the tens digit is 44 (less than 55), we round down to 400400. Step 3: Multiply the estimated numbers. Estimated product = 6000×400=24,00,0006000 \times 400 = 24,00,000.

Explanation:

Rounding to the nearest hundred helps simplify the multiplication process while providing a reasonably accurate approximation of the final product.