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Algebra - Use of Variables in Common Rules

Grade 6CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A variable is a literal number or a letter like x,y,z,l,mx, y, z, l, m or nn that represents a value that is not fixed. It is used in rules and formulas to represent any number in a set of possibilities.

Perimeter of a Square: In geometry, a square has four equal sides. If we represent the length of one side with the variable ss, the rule for the perimeter PP is found by adding the four sides (s+s+s+ss + s + s + s), which simplifies to P=4sP = 4s. Visually, this represents the total length of the outer boundary of the square.

Perimeter of a Rectangle: A rectangle has two equal lengths (ll) and two equal breadths (bb). To find the total boundary length, we add all sides: l+b+l+bl + b + l + b. This is expressed as 2l+2b2l + 2b or 2(l+b)2(l + b). You can visualize this as walking around a rectangular field and covering each dimension twice.

Commutative Property of Addition: This arithmetic rule states that the order in which two numbers are added does not change the result. Using variables aa and bb to represent any two numbers, we write the rule as a+b=b+aa + b = b + a. For example, 5+105 + 10 gives the same result as 10+510 + 5.

Commutative Property of Multiplication: Similar to addition, the product of two numbers remains the same regardless of their order. Using variables aa and bb, the rule is expressed as a×b=b×aa \times b = b \times a. This can be visualized as an array of dots; whether you look at it as aa rows of bb or bb rows of aa, the total count remains the same.

Distributive Property: This rule explains how multiplication is distributed over addition. If we have three numbers a,b,a, b, and cc, the rule is a×(b+c)=(a×b)+(a×c)a \times (b + c) = (a \times b) + (a \times c). Imagine a large rectangle with width aa and length (b+c)(b + c); its total area is equal to the sum of the areas of two smaller rectangles (a×ba \times b and a×ca \times c).

Pattern Rules using Variables: Variables are used to generalize patterns. For instance, if forming one 'L' shape requires 2 matchsticks, two 'L' shapes require 4, and three 'L' shapes require 6, we can generalize that for nn shapes, the number of sticks required is 2n2n.

📐Formulae

Perimeter of a square: P=4sP = 4s

Perimeter of a rectangle: P=2(l+b)P = 2(l + b) or P=2l+2bP = 2l + 2b

Commutativity of addition: a+b=b+aa + b = b + a

Commutativity of multiplication: a×b=b×aa \times b = b \times a

Distributivity of multiplication over addition: a×(b+c)=(a×b)+(a×c)a \times (b + c) = (a \times b) + (a \times c)

Associativity of addition: (a+b)+c=a+(b+c)(a + b) + c = a + (b + c)

💡Examples

Problem 1:

The side of a regular hexagon (a polygon with 6 equal sides) is denoted by ll. Express the perimeter of the hexagon using the variable ll.

Solution:

  1. A regular hexagon has 6 sides of equal length.
  2. Let the length of each side be ll.
  3. Perimeter is the total distance around the boundary, which is the sum of all sides.
  4. Perimeter = l+l+l+l+l+ll + l + l + l + l + l
  5. Perimeter = 6l6l

Explanation:

We use the variable ll to represent the length of one side. Since all six sides are equal in a regular hexagon, we multiply the side length by 6 to get the general rule for its perimeter.

Problem 2:

Leela is Radhika's younger sister. Leela is 4 years younger than Radhika. Can you write Leela's age in terms of Radhika's age? (Take Radhika's age to be xx years).

Solution:

  1. Let Radhika's age be xx years.
  2. Leela is 4 years younger than Radhika.
  3. To find Leela's age, we subtract 4 from Radhika's age.
  4. Leela's age = (x4)(x - 4) years.

Explanation:

Here, xx is a variable representing Radhika's age. By using the expression x4x - 4, we create a general rule that calculates Leela's age regardless of what Radhika's actual age is.