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Algebra - Expressions with Variables

Grade 6CBSE

Review the key concepts, formulae, and examples before starting your quiz.

๐Ÿ”‘Concepts

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Introduction to Variables: A variable is a letter or symbol that represents an unknown quantity whose value can change. In Grade 6, we often use x,y,z,l,x, y, z, l, or nn. Visually, imagine a variable as a 'mystery box' or an empty container where you can place different numbers at different times.

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Constants: A constant is a value that never changes, such as 5,โˆ’12,34,5, -12, \frac{3}{4}, or 100100. Unlike variables, which are like shifting clouds, constants are like solid rocks that remain the same size and shape regardless of the situation.

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Algebraic Expressions: An expression is a mathematical phrase created by combining variables and constants using operations like addition (++), subtraction (โˆ’-), multiplication (ร—\times), and division (รท\div). For example, 3x+53x + 5 is an expression. Visualizing an expression is like looking at a recipe where some ingredients are fixed (constants) and some can be adjusted (variables).

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Terms and Coefficients: In an expression like 4y+74y + 7, the parts separated by ++ or โˆ’- signs are called 'terms'. Here, 4y4y and 77 are terms. In the term 4y4y, the number 44 is called the numerical coefficient of the variable yy. You can visualize this as a tree diagram: the whole expression is the trunk, terms are the main branches, and coefficients/variables are the smaller twigs.

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Forming Expressions from Phrases: Word problems are translated into algebraic expressions by identifying keywords. For instance, '8 more than pp' becomes p+8p + 8, and 'the product of xx and 10' becomes 10x10x. Think of this as translating English sentences into a shorthand mathematical code.

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Variables in Geometry Rules: Variables allow us to write general rules for shapes. If ss represents the side of a square, the perimeter is s+s+s+s=4ss + s + s + s = 4s. Visually, if you look at a square with four sides labeled ss, the variable ss acts as a placeholder for any side length you choose.

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The Distributive Property: This property shows how multiplication relates to addition, written as a(b+c)=ab+aca(b + c) = ab + ac. Visualizing this involves an area model: a large rectangle with width aa and length divided into two parts bb and cc. The total area (a(b+c)a(b+c)) is the sum of the two smaller rectangles (abab and acac).

๐Ÿ“Formulae

Perimeter of a square with side ss: P=4sP = 4s

Perimeter of a rectangle with length ll and breadth bb: P=2(l+b)P = 2(l + b)

Perimeter of an equilateral triangle with side aa: P=3aP = 3a

Commutative property of addition: a+b=b+aa + b = b + a

Commutative property of multiplication: aร—b=bร—aa \times b = b \times a

Distributive property of multiplication over addition: a(b+c)=ab+aca(b + c) = ab + ac

General term for a sequence (e.g., for 2,4,6,...2, 4, 6, ...): 2n2n (where nn is the position)

๐Ÿ’กExamples

Problem 1:

Write the algebraic expression for the statement: '5 subtracted from the product of 2 and mm'. Find its value if m=6m = 6.

Solution:

  1. Identify the 'product of 2 and mm': 2ร—m=2m2 \times m = 2m.
  2. '5 subtracted from' that product: 2mโˆ’52m - 5.
  3. To find the value when m=6m = 6, substitute 6 for mm: 2(6)โˆ’52(6) - 5.
  4. Calculate: 12โˆ’5=712 - 5 = 7.

Explanation:

We first translate the verbal phrase into a two-step mathematical expression and then use the substitution method to calculate a specific numerical result.

Problem 2:

Rohan's father is 4 years more than 3 times Rohan's age. If Rohan's age is yy years, express his father's age in terms of yy.

Solution:

  1. Let Rohan's age be yy.
  2. '3 times Rohan's age' is 3ร—y=3y3 \times y = 3y.
  3. '4 years more than' that is 3y+43y + 4.
  4. Therefore, Father's age = 3y+43y + 4.

Explanation:

This problem demonstrates how to use variables to model a real-world relationship between two different ages by identifying the multiplier (3) and the additional constant (4).