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Factors and Multiples - Divisibility Rules

Grade 5ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Factors and Multiples: Factors are the numbers that divide a given number exactly without leaving a remainder. Multiples are the products obtained when a number is multiplied by other whole numbers. For example, if we have 5×4=205 \times 4 = 20, then 55 and 44 are factors of 2020, and 2020 is a multiple of both 55 and 44.

Divisibility by 2, 5, and 10: These rules depend on the last digit of the number. A number is divisible by 22 if the digit at the ones place is even (0,2,4,6,80, 2, 4, 6, 8). A number is divisible by 55 if it ends in 00 or 55. A number is divisible by 1010 if the ones digit is exactly 00. Imagine a number line where only numbers ending in these specific digits 'jump' into the divisibility group.

Divisibility by 3 and 9: These rules depend on the sum of the digits. For 33, add all digits of the number; if the sum is a multiple of 33, the number is divisible by 33. Similarly, for 99, if the sum of the digits is divisible by 99, the whole number is divisible by 99. Visualize 'breaking apart' the number into its individual digits and stacking them to see if the total height matches a multiple of 33 or 99.

Divisibility by 4 and 8: For 44, check only the last two digits; if they form a number divisible by 44, the whole number is. For 88, check the last three digits. For example, in the number 1,5241,524, focus only on the '24' to determine divisibility by 44.

Divisibility by 6: A number is divisible by 66 if it satisfies the rules for both 22 and 33. This means the number must be even (ends in 0,2,4,6,80, 2, 4, 6, 8) AND the sum of its digits must be a multiple of 33.

Divisibility by 11: To check for 1111, find the sum of digits at odd places and the sum of digits at even places. Subtract the smaller sum from the larger sum. If the difference is 00 or a multiple of 1111 (like 11,22,3311, 22, 33), the number is divisible by 1111. Visualize the digits in a 'see-saw' pattern, alternating between the left and right sides.

Relationship between Factors and Multiples: Every number is a factor of itself and 11 is a factor of every number. A number is always greater than or equal to its factors, and a number is always less than or equal to its multiples (excluding zero).

Prime and Composite Numbers: A Prime number has exactly two factors (11 and itself), such as 2,3,5,72, 3, 5, 7. A Composite number has more than two factors, such as 4,6,8,94, 6, 8, 9. Note that 11 is neither prime nor composite.

📐Formulae

Sum of Digits=d1+d2+d3++dn\text{Sum of Digits} = d_1 + d_2 + d_3 + \dots + d_n

Difference for Divisibility by 11=(Sum of digits at odd places)(Sum of digits at even places)\text{Difference for Divisibility by 11} = |(\text{Sum of digits at odd places}) - (\text{Sum of digits at even places})|

Dividend=(Divisor×Quotient)+Remainder\text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder}

Divisibility condition: Remainder=0\text{Divisibility condition: } \text{Remainder} = 0

💡Examples

Problem 1:

Check if the number 4,7344,734 is divisible by 66.

Solution:

Step 1: Check divisibility by 22. The last digit is 44, which is even. So, 4,7344,734 is divisible by 22. \nStep 2: Check divisibility by 33. Sum of digits =4+7+3+4=18= 4 + 7 + 3 + 4 = 18. Since 1818 is a multiple of 33 (3×6=183 \times 6 = 18), the number is divisible by 33. \nStep 3: Conclusion. Since the number is divisible by both 22 and 33, it is divisible by 66.

Explanation:

This approach uses the compound rule for 66. We first verify the 'even' condition and then the 'sum of digits' condition.

Problem 2:

Determine if 1,3311,331 is divisible by 1111.

Solution:

Step 1: Identify digits at odd and even places starting from the right. \nOdd places: 11 (1st digit) and 33 (3rd digit). Sum =1+3=4= 1 + 3 = 4. \nEven places: 33 (2nd digit) and 11 (4th digit). Sum =3+1=4= 3 + 1 = 4. \nStep 2: Calculate the difference. Difference =44=0= 4 - 4 = 0. \nStep 3: Apply the rule. Since the difference is 00, the number 1,3311,331 is divisible by 1111.

Explanation:

The rule for 1111 requires comparing the sums of alternating digits. A difference of 00 confirms divisibility.