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Number Sense and Operations - Multiplication and Division of Large Numbers

Grade 5IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Standard Algorithm for Multiplication: To multiply large numbers, align them vertically by place value. Multiply the top number by the ones digit of the bottom number. On the next line, place a 00 in the ones column as a placeholder and multiply the top number by the tens digit. Add these partial products together. Visually, this is like stacking two smaller rectangular areas to find a total area.

Long Division (DMSBR): This process involves the steps: Divide, Multiply, Subtract, Bring down, and Repeat. Imagine a division 'house' or bracket where the dividend (total amount) sits inside and the divisor (number of groups) sits outside. The quotient (answer) is recorded on the roof of the house as you work through each place value from left to right.

The Area Model: This visual concept represents multiplication by splitting a rectangle into sections based on place value. For example, for 25×1425 \times 14, draw a rectangle with side lengths of 20+520 + 5 and 10+410 + 4. Calculate the area of the four resulting boxes (20×10,20×4,5×10,5×420 \times 10, 20 \times 4, 5 \times 10, 5 \times 4) and sum them to find the total product.

Multiplying and Dividing by Powers of 1010: When multiplying by 1010, 100100, or 1,0001,000, digits shift to the left on a place value chart. Visually, this adds nn zeros to the end of the number. When dividing by powers of 1010, digits shift to the right, which removes zeros or moves the decimal point to the left.

The Inverse Relationship: Multiplication and division are opposite operations. If you know 25×4=10025 \times 4 = 100, you also know 100÷4=25100 \div 4 = 25. This can be visualized using a 'Fact Family' triangle where the product/dividend is at the top peak and the factors/divisor/quotient are at the base corners.

Interpreting Remainders: In division, the remainder represents the part left over that is smaller than the divisor. Visually, if you are sharing 1313 apples among 44 people, each person gets 33 apples and 11 apple remains. Depending on the question, you might round up (if you need more boxes), ignore the remainder, or turn it into a fraction: RemainderDivisor\frac{Remainder}{Divisor}.

Estimation and Reasonableness: Before solving a complex problem, round the numbers to the nearest 1010 or 100100. For 589×22589 \times 22, estimate as 600×20=12,000600 \times 20 = 12,000. If your calculated answer is close to this estimate, it is likely correct. This acts as a 'mental check' to prevent large errors.

The Distributive Property: This property allows you to break a large number into easier parts. For example, 7×1057 \times 105 can be thought of as 7×(100+5)7 \times (100 + 5). You multiply 7×1007 \times 100 and 7×57 \times 5 separately and then add the results (700+35=735700 + 35 = 735).

📐Formulae

Dividend=(Divisor×Quotient)+RemainderDividend = (Divisor \times Quotient) + Remainder

a×(b+c)=(a×b)+(a×c)a \times (b + c) = (a \times b) + (a \times c)

a×b=b×aa \times b = b \times a

Remainder<DivisorRemainder < Divisor

💡Examples

Problem 1:

Calculate the product of 342×25342 \times 25 using the standard algorithm.

Solution:

  1. Multiply 342342 by the ones digit (55): 342×5=1,710342 \times 5 = 1,710.
  2. Multiply 342342 by the tens digit (22). First, place a 00 in the ones column: 342×20=6,840342 \times 20 = 6,840.
  3. Add the two partial products: 1,710+6,840=8,5501,710 + 6,840 = 8,550.

Explanation:

We use place value to break the multiplication into two steps: 342×5342 \times 5 and 342×20342 \times 20, then combine the results for the final product.

Problem 2:

Divide 1,5781,578 by 1212 and identify the quotient and remainder.

Solution:

  1. Divide: 1212 goes into 1515 one time (1×12=121 \times 12 = 12). Subtract: 1512=315 - 12 = 3.
  2. Bring down: Bring down the 77 to make 3737. Divide: 1212 goes into 3737 three times (3×12=363 \times 12 = 36). Subtract: 3736=137 - 36 = 1.
  3. Bring down: Bring down the 88 to make 1818. Divide: 1212 goes into 1818 one time (1×12=121 \times 12 = 12). Subtract: 1812=618 - 12 = 6.
  4. Result: The quotient is 131131 and the remainder is 66.

Explanation:

Using the DMSB method, we process the dividend from left to right. Since 66 is less than our divisor 1212 and there are no more digits to bring down, it becomes the remainder.