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Large Numbers - Word Problems on Speed and Distance

Grade 5CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Understanding Distance: Distance is the total path covered by an object. In large number problems, distances can range from hundreds to lakhs of kilometers. Imagine a long straight line on a map representing the path from one city to another, with markers every 1000km1000 km.

Understanding Speed: Speed tells us how fast an object is moving or how much distance is covered in a specific unit of time (like 1 hour). Think of a car's speedometer where the needle points to a number like 6060, indicating the car covers 60km60 km every hour.

Understanding Time: Time is the duration taken to cover a certain distance. For large numbers, we often use hours. Picture a clock face where the hands move to show the start and end of a long journey.

The Magic Triangle: Visualize a triangle divided into three parts: Distance(D)Distance (D) at the top peak, and Speed(S)Speed (S) and Time(T)Time (T) at the bottom two corners. This visual helps remember that to find the top (DD), you multiply the bottom two (S×TS \times T), and to find a bottom part, you divide the top by the other bottom part.

Units of Measurement: Always ensure units match. Common units include kilometers (kmkm) for distance, hours (hh) for time, and km/hkm/h for speed. If a distance is in kmkm and time is in minutesminutes, you may need to convert minutes to hours by dividing by 6060.

Large Number Calculations: When solving word problems, you will often encounter numbers in thousands or lakhs (e.g., 1,50,000km1,50,000 km). Use a place value chart to align digits correctly during multiplication or division to avoid errors with zeros.

Constant Speed Assumption: In Grade 5 problems, we usually assume the object moves at a 'uniform' or 'constant' speed, meaning it doesn't slow down or speed up. Imagine a train moving steadily across a flat landscape without stopping.

📐Formulae

Speed=DistanceTimeSpeed = \frac{Distance}{Time}

Distance=Speed×TimeDistance = Speed \times Time

Time=DistanceSpeedTime = \frac{Distance}{Speed}

1 km=1000 meters1 \text{ km} = 1000 \text{ meters}

1 hour=60 minutes1 \text{ hour} = 60 \text{ minutes}

💡Examples

Problem 1:

A high-speed train travels at a constant speed of 120km/h120 km/h. How much distance will it cover in 15hours15 hours?

Solution:

  1. Identify the given values: Speed (SS) = 120km/h120 km/h, Time (TT) = 15hours15 hours. \ 2. Use the formula for Distance: Distance=Speed×TimeDistance = Speed \times Time. \ 3. Substitute the values: Distance=120×15Distance = 120 \times 15. \ 4. Perform the multiplication: 120×10=1200120 \times 10 = 1200 and 120×5=600120 \times 5 = 600. 1200+600=18001200 + 600 = 1800. \ 5. Result: The train covers 1800km1800 km.

Explanation:

To find the total distance, we multiply the speed of the train by the total number of hours it traveled.

Problem 2:

An airplane needs to cover a total distance of 4,50,000km4,50,000 km over several trips. If it flies at a speed of 900km/h900 km/h, how many hours will it take in total?

Solution:

  1. Identify the given values: Distance (DD) = 4,50,000km4,50,000 km, Speed (SS) = 900km/h900 km/h. \ 2. Use the formula for Time: Time=DistanceSpeedTime = \frac{Distance}{Speed}. \ 3. Substitute the values: Time=4,50,000900Time = \frac{4,50,000}{900}. \ 4. Simplify the calculation by canceling zeros: 45009\frac{4500}{9}. \ 5. Perform the division: 45÷9=545 \div 9 = 5, so 4500÷9=5004500 \div 9 = 500. \ 6. Result: It will take 500hours500 hours.

Explanation:

To find the time taken, we divide the large distance value by the speed. Canceling the common zeros in the numerator and denominator makes the division of large numbers much easier.