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Large Numbers - Large Number Operations

Grade 5CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Place Value Alignment: When adding or subtracting large numbers, digits must be aligned vertically according to their place values (Ones under Ones, Tens under Tens, etc.). Visually, this creates a grid-like structure where columns represent Lakhs, Ten-thousands, Thousands, Hundreds, Tens, and Ones.

Addition with Carrying: If the sum of digits in a specific place value column exceeds 99, the tens digit is 'carried over' to the next higher place value column on the left. In a written sum, these carried digits are usually written as small numbers at the top of the next column.

Subtraction with Borrowing: If a digit in the minuend is smaller than the digit in the subtrahend at the same place value, we 'borrow' 11 from the column to the immediate left. Visually, we cross out the digit on the left, decrease its value by 11, and add 1010 to the current column's digit.

Multi-digit Multiplication: Multiplying large numbers involves calculating partial products. For example, when multiplying by a two-digit number like 4545, we first multiply by the ones digit (55) and then by the tens digit (4040, represented by putting a 00 in the ones place). The final product is the sum of these partial products arranged in horizontal rows.

Long Division Process: Division is represented visually using a division bracket where the Dividend is inside, the Divisor is to the left, and the Quotient is written on top. The process follows the steps: Divide, Multiply, Subtract, and Bring Down.

Properties of Zero and One: Any large number multiplied by 11 remains the same (a×1=aa \times 1 = a). Any number multiplied by 00 results in 00 (a×0=0a \times 0 = 0). In division, 00 divided by any number is 00, but division by 00 is not defined.

Estimation in Operations: Estimation involves rounding large numbers to the nearest 1010, 100100, or 1,0001,000 before performing an operation. This is visually useful for checking if a calculated answer is 'in the right ballpark' or reasonable.

📐Formulae

Sum=Addend1+Addend2\text{Sum} = \text{Addend}_1 + \text{Addend}_2

Difference=MinuendSubtrahend\text{Difference} = \text{Minuend} - \text{Subtrahend}

Product=Multiplicand×Multiplier\text{Product} = \text{Multiplicand} \times \text{Multiplier}

Dividend=(Divisor×Quotient)+Remainder\text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder}

Remainder<Divisor\text{Remainder} < \text{Divisor}

💡Examples

Problem 1:

Find the sum of 5,43,2105,43,210 and 2,87,6542,87,654.

Solution:

Step 1: Align the numbers vertically by place value. 5,43,2105,43,210 +2,87,654+ 2,87,654 \rule{2cm}{0.4pt} Step 2: Add Ones: 0+4=40 + 4 = 4 Step 3: Add Tens: 1+5=61 + 5 = 6 Step 4: Add Hundreds: 2+6=82 + 6 = 8 Step 5: Add Thousands: 3+7=103 + 7 = 10. Write 00, carry 11 to Ten-thousands. Step 6: Add Ten-thousands: 4+8+1(carry)=134 + 8 + 1 (carry) = 13. Write 33, carry 11 to Lakhs. Step 7: Add Lakhs: 5+2+1(carry)=85 + 2 + 1 (carry) = 8. Final Sum: 8,30,8648,30,864

Explanation:

The numbers are added column by column starting from the right. Carrying is used when the sum of a column is 1010 or more.

Problem 2:

Divide 4,5604,560 by 1212.

Solution:

Step 1: Set up the long division: 1212 into 45604560. Step 2: 1212 goes into 4545 three times (12×3=3612 \times 3 = 36). Subtract 3636 from 4545 to get 99. Step 3: Bring down the 66 to make 9696. 1212 goes into 9696 exactly 88 times (12×8=9612 \times 8 = 96). Step 4: Subtract 9696 from 9696 to get 00. Step 5: Bring down the last 00. 1212 goes into 00 zero times. Quotient: 380380, Remainder: 00.

Explanation:

This follows the standard long division algorithm. Since 12×380=4,56012 \times 380 = 4,560, the division is exact with no remainder.