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Number System - Roman Numerals

Grade 4ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Roman numeral system uses seven basic capital letters of the English alphabet as symbols: I=1I = 1, V=5V = 5, X=10X = 10, L=50L = 50, C=100C = 100, D=500D = 500, and M=1000M = 1000. Unlike our standard Hindu-Arabic system, there is no symbol for zero in Roman numerals.

Rule of Repetition: When a symbol is repeated, its value is added as many times as it occurs. For example, II=1+1=2II = 1 + 1 = 2 and XXX=10+10+10=30XXX = 10 + 10 + 10 = 30. Note that the symbols II, XX, CC, and MM can be repeated a maximum of three times, whereas VV, LL, and DD are never repeated.

Rule of Addition: If a symbol of smaller value is written to the right of a symbol of greater value, we add their values. Imagine a ladder where the steps go down in value: VI=5+1=6VI = 5 + 1 = 6 and LX=50+10=60LX = 50 + 10 = 60.

Rule of Subtraction: If a symbol of smaller value is written to the left of a symbol of greater value, we subtract the smaller value from the greater value. For example, IV=51=4IV = 5 - 1 = 4 and XC=10010=90XC = 100 - 10 = 90.

Constraints on Subtraction: The symbols VV, LL, and DD are never subtracted. The symbol II can be subtracted from VV and XX only. The symbol XX can be subtracted from LL and CC only. For example, to write 9595, we cannot write VCVC; we must write 90+5=XCV90 + 5 = XCV.

Writing Large Numbers: To write numbers greater than 1010 in Roman numerals, we first break the number into thousands, hundreds, tens, and ones. For example, 4848 is viewed as 40+840 + 8, which is written as (5010)+(5+3)=XLVIII(50 - 10) + (5 + 3) = XLVIII.

📐Formulae

I=1,V=5,X=10,L=50,C=100,D=500,M=1000I = 1, V = 5, X = 10, L = 50, C = 100, D = 500, M = 1000

\text{Addition Rule: } \text{Value} = \text{Greater Value} + \text{Smaller Value (if written to the right)}$

\text{Subtraction Rule: } \text{Value} = \text{Greater Value} - \text{Smaller Value (if written to the left)}$

\text{Maximum Repetition} = 3 \text{ times (for } I, X, C, M \text{ only)}$

💡Examples

Problem 1:

Convert the Hindu-Arabic numeral 9494 into a Roman numeral.

Solution:

Step 1: Break the number 9494 into tens and ones: 94=90+494 = 90 + 4. \ Step 2: Write the Roman numeral for 9090. Since we cannot repeat XX nine times, we use the subtraction rule: 90=10010=XC90 = 100 - 10 = XC. \ Step 3: Write the Roman numeral for 44. Using the subtraction rule: 4=51=IV4 = 5 - 1 = IV. \ Step 4: Combine the parts: XC+IV=XCIVXC + IV = XCIV.

Explanation:

To convert a number like 9494, we decompose it into place values. We represent 9090 as XCXC (10 subtracted from 100) and 44 as IVIV (1 subtracted from 5) to follow the subtraction rules.

Problem 2:

Convert the Roman numeral LXXVILXXVI into a Hindu-Arabic numeral.

Solution:

Step 1: Identify the value of each symbol: L=50L = 50, X=10X = 10, V=5V = 5, I=1I = 1. \ Step 2: Check for subtraction or addition rules. Since symbols are arranged in decreasing order (or equal), we use the addition rule. \ Step 3: L+X+X+V+I=50+10+10+5+1L + X + X + V + I = 50 + 10 + 10 + 5 + 1. \ Step 4: Add the values: 50+10+10+5+1=7650 + 10 + 10 + 5 + 1 = 76.

Explanation:

When symbols are placed from largest to smallest, we simply sum their values. Here, LL (50) is followed by two XXs (20), a VV (5), and an II (1), totaling 7676.