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Multiplication - Multiplication by 2 and 3-digit numbers

Grade 4ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Multiplication is the process of repeated addition. For example, 15×315 \times 3 is the same as 15+15+1515 + 15 + 15. In the equation 24×5=12024 \times 5 = 120, 2424 is called the Multiplicand, 55 is the Multiplier, and 120120 is the Product. Visually, this is arranged in vertical columns where the multiplier is placed under the multiplicand.

When multiplying by 10,100,10, 100, or 10001000, we use a shortcut. Simply write the multiplicand and append the number of zeros present in the multiplier. For instance, 45×100=450045 \times 100 = 4500. In a place value chart, this looks like shifting the digits of the original number to the left and filling the empty units and tens places with zeros.

The Standard Algorithm for 2 and 3-digit multiplication involves 'Partial Products'. When multiplying 123×25123 \times 25, you first multiply 123123 by 55 (ones place) and then by 2020 (tens place). These two results are called partial products and are added together at the end. Visually, these are written in separate rows below the main problem.

The 'Place Holder Zero' is crucial when multiplying by the tens or hundreds digit. When you move to multiply by the tens digit of the multiplier, you must place a 00 in the ones column of that row because you are actually multiplying by a multiple of 1010. If multiplying by the hundreds digit, you place two zeros (0000) as placeholders.

Regrouping or 'Carrying Over' occurs when the product of digits in one column exceeds 99. The tens digit of that product is carried over to the next place value column (to the left) and is added after the next multiplication step. Visually, these carried numbers are written in a smaller font size above the multiplicand digits.

The Distributive Property allows us to break down large numbers to make multiplication easier. For example, 35×1235 \times 12 can be visually represented as 35×(10+2)35 \times (10 + 2), which equals (35×10)+(35×2)(35 \times 10) + (35 \times 2). This can be imagined as splitting a large grid into two smaller, manageable sections.

Properties of Multiplication include the Commutative Property (changing the order of numbers does not change the product: 12×5=5×1212 \times 5 = 5 \times 12) and the Zero Property (any number multiplied by 00 is 00). Visually, the commutative property is like rotating an array of dots by 90 degrees; the total number of dots remains the same.

📐Formulae

Multiplicand×Multiplier=ProductMultiplicand \times Multiplier = Product

a×b=b×aa \times b = b \times a (Commutative Property)

a×(b+c)=(a×b)+(a×c)a \times (b + c) = (a \times b) + (a \times c) (Distributive Property)

a×1=aa \times 1 = a (Identity Property)

a×0=0a \times 0 = 0 (Zero Property)

💡Examples

Problem 1:

Find the product of 245245 and 3434.

Solution:

Step 1: Multiply 245245 by the ones digit (44): 245×4=980245 \times 4 = 980 Step 2: Multiply 245245 by the tens digit (33). Put a 00 in the ones place first: 245×30=7350245 \times 30 = 7350 Step 3: Add the partial products: 980+7350=8330980 + 7350 = 8330 Therefore, 245×34=8330245 \times 34 = 8330.

Explanation:

We use the standard vertical algorithm. First, we multiply the entire multiplicand by 44. Then, we shift to the tens place of the multiplier (33); we place a zero placeholder and multiply 245245 by 33. Finally, we sum both results.

Problem 2:

Multiply 156156 by 1212.

Solution:

Step 1: Multiply 156156 by 22 (ones place): 156×2=312156 \times 2 = 312 Step 2: Multiply 156156 by 11 (tens place), adding a 00 placeholder: 156×10=1560156 \times 10 = 1560 Step 3: Add the partial products together: 312+1560=1872312 + 1560 = 1872 So, 156×12=1872156 \times 12 = 1872.

Explanation:

This demonstrates a 3-digit by 2-digit multiplication. The key is to remember the carry-over during the first step (2×6=122 \times 6 = 12, carry 11; 2×5=10+1=112 \times 5 = 10 + 1 = 11, carry 11; 2×1=2+1=32 \times 1 = 2 + 1 = 3) and the placeholder zero in the second step.