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Multiplication - Multiplication by 10, 100, and 1000

Grade 4ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Multiplying by 1010: To multiply any whole number by 1010, simply write the number and place one zero at its end. For example, 56×10=56056 \times 10 = 560. Visually, this is equivalent to shifting every digit in the number one place to the left on a place value chart, leaving the ones place empty to be filled by a 00.

Multiplying by 100100: To multiply a whole number by 100100, write the number and place two zeros at the end. For instance, 14×100=140014 \times 100 = 1400. In terms of place value, each digit shifts two positions to the left (e.g., a digit in the ones place moves to the hundreds place).

Multiplying by 10001000: To multiply a whole number by 10001000, write the number and place three zeros at the end. For example, 8×1000=80008 \times 1000 = 8000. Imagine the number moving three steps to the left across the place value columns: Ones \rightarrow Tens \rightarrow Hundreds \rightarrow Thousands.

Multiplying by Multiples of 1010: When multiplying by numbers like 20,30,,9020, 30, \dots, 90, multiply the non-zero digits first and then append one zero. For 15×3015 \times 30, you calculate 15×3=4515 \times 3 = 45 and then add one zero to get 450450.

Multiplying by Multiples of 100100 and 10001000: Similar to multiples of 1010, multiply the basic numbers first and then append the total count of zeros. For 12×40012 \times 400, multiply 12×4=4812 \times 4 = 48 and add two zeros to get 48004800. For 5×60005 \times 6000, multiply 5×6=305 \times 6 = 30 and add three zeros to get 30,00030,000.

The Shift Rule: Every time we multiply by a factor of 1010, the value of the number increases ten-fold. Visually, you can think of this as a number 'growing' and sliding to the left while 00 acts as a placeholder to maintain the new, higher place values.

📐Formulae

n×10=n0n \times 10 = n0

n×100=n00n \times 100 = n00

n×1000=n000n \times 1000 = n000

a×(b×10)=(a×b)×10a \times (b \times 10) = (a \times b) \times 10

a×(b×100)=(a×b)×100a \times (b \times 100) = (a \times b) \times 100

💡Examples

Problem 1:

Find the product of 245×100245 \times 100.

Solution:

Step 1: Identify the number of zeros in the multiplier. Here, 100100 has two zeros. Step 2: Write the original number, 245245. Step 3: Append the two zeros to the right of 245245. 245×100=24,500245 \times 100 = 24,500

Explanation:

When multiplying by 100100, we use the rule of appending two zeros to the end of the multiplicand. This shifts 245245 from the hundreds place to the ten-thousands place.

Problem 2:

Calculate 12×400012 \times 4000.

Solution:

Step 1: Separate the multiple of 10001000 into a digit and 10001000: 4000=4×10004000 = 4 \times 1000. Step 2: Multiply the non-zero digits: 12×4=4812 \times 4 = 48. Step 3: Multiply the result by 10001000 by adding three zeros to the end. 48×1000=48,00048 \times 1000 = 48,000 So, 12×4000=48,00012 \times 4000 = 48,000.

Explanation:

This approach breaks the problem into two easier steps: basic multiplication and then applying the rule for multiplying by 10001000.