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Division - Properties of Division

Grade 4ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The terms of division consist of the Dividend (the total number to be divided), the Divisor (the number of groups or the number in each group), the Quotient (the answer), and the Remainder (the amount left over). For example, in 17÷5=317 \div 5 = 3 with a remainder of 22, 1717 is the dividend and 55 is the divisor. Visually, imagine 1717 dots arranged in rows of 55; you will have 33 full rows and 22 extra dots leftover.

Property of 1: When any number is divided by 11, the quotient is the number itself. For example, 45÷1=4545 \div 1 = 45. This means if you have 4545 items and put them into 11 big group, that group still contains all 4545 items.

Property of Self: When a non-zero number is divided by itself, the quotient is always 11. For example, 12÷12=112 \div 12 = 1. Visually, if you have 1212 chocolates and share them among 1212 friends, each friend gets exactly 11 chocolate.

Division of Zero: When zero is divided by any number (except zero), the quotient is always 00. For example, 0÷8=00 \div 8 = 0. If you have 00 toys to distribute among 88 children, each child will receive 00 toys.

Division by Zero: Dividing a number by zero is not defined and is not possible in mathematics. You cannot take a quantity and split it into zero groups or share it with zero people. In a division bracket, you can never have 00 as the divisor on the outside.

Inverse Relation: Division is the inverse operation of multiplication. Every multiplication fact provides a division fact. If 8×4=328 \times 4 = 32, then it follows that 32÷4=832 \div 4 = 8 and 32÷8=432 \div 8 = 4. This can be visualized as an array of dots where the total (3232) can be split into either rows or columns.

The Remainder Rule: In any division problem, the Remainder must always be smaller than the Divisor (Remainder<DivisorRemainder < Divisor). If the remainder is equal to or larger than the divisor, it means another full group could have been made. For example, when dividing by 44, the only possible remainders are 0,1,2,0, 1, 2, or 33.

📐Formulae

Dividend=(Divisor×Quotient)+Remainder\text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder}

a÷1=aa \div 1 = a

a÷a=1 (where a0)a \div a = 1 \text{ (where } a \neq 0)

0÷a=0 (where a0)0 \div a = 0 \text{ (where } a \neq 0)

💡Examples

Problem 1:

Divide 5858 by 77 and verify the result using the division properties and formula.

Solution:

Step 1: Find how many times 77 goes into 5858. We know 7×8=567 \times 8 = 56. Step 2: Subtract to find the remainder: 5856=258 - 56 = 2. Step 3: Identify terms: Quotient = 88, Remainder = 22. Step 4: Verify using the formula: (7×8)+2=56+2=58(7 \times 8) + 2 = 56 + 2 = 58.

Explanation:

The division formula states that the dividend is equal to the product of the divisor and quotient plus the remainder. Since 5858 matches our original dividend, the division is correct.

Problem 2:

Solve the following using properties of division: (a) 256÷256256 \div 256 (b) 0÷990 \div 99 (c) 1,025÷11,025 \div 1

Solution:

Step 1 (a): Use the Property of Self. Any non-zero number divided by itself is 11. So, 256÷256=1256 \div 256 = 1. Step 2 (b): Use the Division of Zero property. 00 divided by any number is 00. So, 0÷99=00 \div 99 = 0. Step 3 (c): Use the Property of 11. Any number divided by 11 is the number itself. So, 1,025÷1=1,0251,025 \div 1 = 1,025.

Explanation:

These problems are solved instantly by applying the fundamental properties of division without needing long division calculations.