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Building with Bricks - Faces, Edges, and Corners

Grade 4CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A brick is a solid three-dimensional (3D) shape known as a cuboid. Unlike a flat rectangle, it has depth and takes up space. Visual Description: Think of a standard rectangular box or a sponge; it has length, width, and thickness.

A face is the flat surface of a brick. A standard brick has exactly 66 faces, and each face is a rectangle. Visual Description: If you hold a brick, you can see the top, bottom, front, back, and two side surfaces.

An edge is the straight line where two faces of the brick meet. A brick has 1212 edges. Visual Description: These are the long and short straight lines that form the skeleton or the frame of the brick.

A corner (also called a vertex) is the point where three edges of the brick meet. A brick has 88 corners. Visual Description: These are the sharp, pointy tips at the very ends of the brick.

Brick patterns like 'Jaali' and 'Jharokha' are used to decorate walls. A 'Jaali' is a pattern of gaps (holes) in the wall that allows air and light to pass through, while a 'Jharokha' is a type of decorative window pattern. Visual Description: Jaali looks like a net or screen made of bricks, while Jharokha looks like a balcony frame built into the wall.

An Arch is a curved structure made of bricks often found over doors, windows, or bridges. Visual Description: It looks like a semi-circle or a 'U' shape turned upside down, supporting the weight of the wall above it.

Bricks are measured by three dimensions: Length (ll), Breadth (bb), and Height (hh). When drawing a brick, we usually show three faces to give it a 3D look, even though it has six in total.

📐Formulae

Number of Faces=6\text{Number of Faces} = 6

Number of Edges=12\text{Number of Edges} = 12

Number of Corners (Vertices)=8\text{Number of Corners (Vertices)} = 8

Euler’s formula for cuboids: F+VE=2\text{Euler's formula for cuboids: } F + V - E = 2

Cost of Bricks=Price per 1000 bricks1000×Total bricks needed\text{Cost of Bricks} = \frac{\text{Price per 1000 bricks}}{1000} \times \text{Total bricks needed}

💡Examples

Problem 1:

If the price of 10001000 new bricks is Rs. 2000Rs.\ 2000, how much will Muneer pay if he decides to buy 40004000 bricks?

Solution:

Step 1: Identify the price for 10001000 bricks = Rs. 2000Rs.\ 2000. \ Step 2: Determine how many sets of 10001000 are in 40004000. 40001000=4\frac{4000}{1000} = 4. \ Step 3: Multiply the price by 44. 2000×4=Rs. 80002000 \times 4 = Rs.\ 8000.

Explanation:

Since the cost is given for a batch of 1000, we find out how many such batches are needed and multiply the rate by that number.

Problem 2:

Draw a line to represent an edge of a brick. If the length of one edge is 15 cm15\ cm and the breadth is 8 cm8\ cm, calculate the perimeter of one rectangular face of the brick.

Solution:

Step 1: Use the perimeter formula for a rectangle: P=2×(l+b)P = 2 \times (l + b). \ Step 2: Plug in the values: P=2×(15 cm+8 cm)P = 2 \times (15\ cm + 8\ cm). \ Step 3: Calculate the sum: 15+8=23 cm15 + 8 = 23\ cm. \ Step 4: Multiply by 22: 2×23=46 cm2 \times 23 = 46\ cm.

Explanation:

The face of a brick is a rectangle. To find the boundary (perimeter), we add the length and breadth and then double the result.