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Measure - Reading time on analog and digital clocks

Grade 3IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Analog clocks have two main hands: the short hand (hour hand) and the long hand (minute hand).

The clock face is numbered 1 to 12, representing hours, but also representing 60 minutes in total.

Each number on the clock represents a 5-minute interval (e.g., 1 is 5 minutes, 2 is 10 minutes).

Digital clocks use a 4-digit format (HH:MM) to show hours and minutes.

'Past' is used for the first 30 minutes of the hour; 'To' is used for the minutes leading to the next hour.

AM refers to the time from midnight to noon; PM refers to the time from noon to midnight.

📐Formulae

1 hour=60 minutes1 \text{ hour} = 60 \text{ minutes}

1/2 hour=30 minutes (Half past)1/2 \text{ hour} = 30 \text{ minutes (Half past)}

1/4 hour=15 minutes (Quarter past)1/4 \text{ hour} = 15 \text{ minutes (Quarter past)}

Minutes=Number on clock×5\text{Minutes} = \text{Number on clock} \times 5 (for the minute hand)

Quarter to X=(X1):45\text{Quarter to } X = (X-1):45 in digital time

💡Examples

Problem 1:

An analog clock has the hour hand between 4 and 5, and the minute hand is pointing exactly at 6. What is the time in digital format?

Solution:

04:30

Explanation:

Since the minute hand is on 6, we multiply 6×5=306 \times 5 = 30 minutes. The hour hand has passed 4 but not yet reached 5, so the hour is 4. This is 'Half past 4'.

Problem 2:

Convert 'Quarter to 9' into digital time.

Solution:

08:45

Explanation:

'Quarter to 9' means there are 15 minutes left before it becomes 9:00. We subtract 15 minutes from 60 to get 45 minutes, and use the previous hour, which is 8.

Problem 3:

A school bell rings at 10:15. Where will the minute hand be on an analog clock?

Solution:

The minute hand will point to the number 3.

Explanation:

To find the position of the minute hand, divide the minutes by 5. 15÷5=315 \div 5 = 3. This is also known as 'Quarter past 10'.