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Multiplication - Word Problems on Multiplication

Grade 3ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Multiplication is essentially Repeated Addition. When a word problem describes several groups of the same size, you can find the total by multiplying. For example, visualizing 44 baskets with 55 apples each is the same as 5+5+5+55 + 5 + 5 + 5, which is 4×5=204 \times 5 = 20.

In a multiplication sentence, the number being multiplied is called the Multiplicand, the number of times it is multiplied is the Multiplier, and the result is the Product (Multiplicand×Multiplier=ProductMultiplicand \times Multiplier = Product).

Identifying keywords is essential for word problems. Look for words like 'each', 'every', 'per', 'in all', and 'altogether' when equal groups are mentioned. These words often indicate that you need to find a total using multiplication.

The Commutative Property of multiplication states that the order of numbers does not change the result. For example, 3×6=183 \times 6 = 18 and 6×3=186 \times 3 = 18. Visually, this is like looking at an array of dots with 33 rows and 66 columns, then rotating it to see 66 rows and 33 columns; the total count of dots remains 1818.

The Identity Property (Property of One) means any number multiplied by 11 stays the same (15×1=1515 \times 1 = 15). This represents having exactly one group of a certain quantity.

The Zero Property states that any number multiplied by 00 is always 00 (25×0=025 \times 0 = 0). In a word problem context, this is like having multiple empty containers; the total number of items is zero.

For word problems involving larger numbers, use Column Multiplication. Align the numbers vertically by their place values (Ones, Tens, Hundreds). Multiply the multiplier by the ones digit first, then the tens digit, carrying over values to the next column when the product is 1010 or more.

📐Formulae

Multiplicand×Multiplier=Product\text{Multiplicand} \times \text{Multiplier} = \text{Product}

Total Quantity=Quantity in one group×Number of groups\text{Total Quantity} = \text{Quantity in one group} \times \text{Number of groups}

Total Cost=Price per item×Number of items\text{Total Cost} = \text{Price per item} \times \text{Number of items}

💡Examples

Problem 1:

A box contains 3636 pencils. How many pencils are there in 88 such boxes?

Solution:

  1. Number of pencils in one box = 3636
  2. Number of boxes = 88
  3. Total pencils = 36×836 \times 8
  4. Multiply the ones: 6×8=486 \times 8 = 48. Write 88 in the ones place and carry over 44 to the tens place.
  5. Multiply the tens: 3×8=243 \times 8 = 24. Add the carried-over 44: 24+4=2824 + 4 = 28.
  6. The total is 288288.

Explanation:

This is a grouping problem where we know the quantity of one unit (3636) and need to find the total for 88 units. We use the column multiplication method to find the product.

Problem 2:

The cost of one notebook is 45₹ 45. What is the total cost of 99 notebooks?

Solution:

  1. Cost of 11 notebook = 45₹ 45
  2. Number of notebooks = 99
  3. Total cost = 45×945 \times 9
  4. 5×9=455 \times 9 = 45. Write 55, carry over 44.
  5. 4×9=364 \times 9 = 36. Add carry: 36+4=4036 + 4 = 40.
  6. Total cost = 405₹ 405.

Explanation:

To find the total cost, we multiply the price of a single item by the number of items purchased. This demonstrates the 'Price ×\times Quantity' formula.