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Number - Addition and Subtraction with Regrouping

Grade 3IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Place Value Alignment: Before adding or subtracting, digits must be lined up vertically according to their place value (Hundreds,Tens,OnesHundreds, Tens, Ones). Visually, imagine vertical grid lines separating each column to ensure that OnesOnes are stacked over OnesOnes and TensTens are stacked over TensTens.

Regrouping in Addition (Carrying): When the sum of digits in a column is 1010 or more, you must regroup. For example, if the OnesOnes column sum is 1313, you write the 33 in the OnesOnes place and carry the 11 (which represents 1010) over to the TensTens column. Visually, this is represented by writing a small +1+1 above the TensTens digit.

Regrouping in Subtraction (Borrowing): If the top digit in a column is smaller than the bottom digit, you must borrow from the next place value. Visually, this looks like crossing out the digit in the left column, reducing it by 11, and placing a small 11 in front of the digit in your current column to turn it into a 'teen' number (e.g., 22 becomes 1212).

Subtracting Across Zeros: When you need to borrow but the next column is a 00, you must continue to the next place value (like the HundredsHundreds) to borrow. Visually, this creates a chain reaction where the HundredsHundreds digit decreases, the 00 in the TensTens place becomes a 99, and the OnesOnes place finally receives the 1010 it needs.

The Inverse Relationship: Addition and subtraction are opposite operations. You can use addition to check a subtraction problem and vice versa. If ab=ca - b = c, then c+bc + b must equal aa. This is a helpful 'loop' visual to verify if your calculations are correct.

Base-10 Visuals: Addition and subtraction can be modeled using Base-10 blocks. A large square 'flat' represents 100100, a long 'rod' represents 1010, and a tiny 'cube' represents 11. Regrouping is simply swapping 1010 cubes for 11 rod, or breaking 11 rod into 1010 cubes.

📐Formulae

Addend+Addend=SumAddend + Addend = Sum

MinuendSubtrahend=DifferenceMinuend - Subtrahend = Difference

a+b=b+a (Commutative Property)a + b = b + a \text{ (Commutative Property)}

(a+b)+c=a+(b+c) (Associative Property)(a + b) + c = a + (b + c) \text{ (Associative Property)}

If ab=c, then c+b=a\text{If } a - b = c, \text{ then } c + b = a

💡Examples

Problem 1:

Solve the addition problem: 458+275458 + 275

Solution:

  1. Align the numbers: \begin{array}{r@{\quad}l} & 458 \\ + & 275 \\ \hline \end{array}
  2. Add the OnesOnes: 8+5=138 + 5 = 13. Write 33 in the OnesOnes place and carry 11 to the TensTens column.
  3. Add the TensTens: 5+7+1 (carried)=135 + 7 + 1 \text{ (carried)} = 13. Write 33 in the TensTens place and carry 11 to the HundredsHundreds column.
  4. Add the HundredsHundreds: 4+2+1 (carried)=74 + 2 + 1 \text{ (carried)} = 7. Write 77 in the HundredsHundreds place. Final Answer: 733733.

Explanation:

This problem requires regrouping twice: once from the ones to the tens, and once from the tens to the hundreds.

Problem 2:

Solve the subtraction problem: 602348602 - 348

Solution:

  1. Align the numbers: \begin{array}{r@{\quad}l} & 602 \\ - & 348 \\ \hline \end{array}
  2. OnesOnes column: 2<82 < 8, so we must borrow. Since the TensTens place is 00, borrow from the HundredsHundreds.
  3. Regroup the HundredsHundreds: The 66 becomes 55. The 00 in the TensTens place temporarily becomes 1010.
  4. Regroup the TensTens: Borrow from the 1010, so it becomes 99. The 22 in the OnesOnes place becomes 1212.
  5. Subtract OnesOnes: 128=412 - 8 = 4.
  6. Subtract TensTens: 94=59 - 4 = 5.
  7. Subtract HundredsHundreds: 53=25 - 3 = 2. Final Answer: 254254.

Explanation:

This example demonstrates subtracting across a zero, which requires moving two places over to borrow correctly.