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Fun with Numbers - Skip Counting

Grade 3CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Skip counting is a method of counting where we add a fixed number (other than 11) to get the next number in the sequence. Imagine a rabbit hopping over a specific number of stones on a path, landing only on every nn-th stone.

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Skip Counting by 22s follows a pattern where the sequence moves through even or odd numbers by adding 22 each time, such as 2,4,6,8...2, 4, 6, 8... or 1,3,5,7...1, 3, 5, 7.... Visually, this is like counting pairs of socks or shoes where each addition adds two items to the total.

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Skip Counting by 55s is identified by numbers that always end in the digits 00 or 55. A visual way to understand this is by counting the fingers on multiple hands: 5,10,15,205, 10, 15, 20, and so on.

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Skip Counting by 1010s is one of the simplest patterns because only the tens digit changes (until you cross a hundred). For example, 110,120,130,140110, 120, 130, 140. Imagine a tower built with blocks of 1010, where each new block increases the height by exactly 1010 units.

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Skip Counting by 5050s involves large jumps and creates a repeating pattern every two steps, such as 50,100,150,20050, 100, 150, 200. Think of a cricket match where runs are tracked in half-centuries (5050 runs) and full centuries (100100 runs).

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Backward Skip Counting involves subtracting the skip value repeatedly to move down the number line. Imagine a countdown for a rocket launch or walking down a staircase while skipping every second step: 50,48,46,4450, 48, 46, 44.

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To identify the skip counting rule in an unknown sequence, we find the difference between two numbers that are next to each other. On a number line, this represents the 'size' of the jump between points.

📐Formulae

Next Number=Current Number+Skip Value\text{Next Number} = \text{Current Number} + \text{Skip Value}

Previous Number=Current Number−Skip Value\text{Previous Number} = \text{Current Number} - \text{Skip Value}

Skip Value=Second Number−First Number\text{Skip Value} = \text{Second Number} - \text{First Number}

💡Examples

Problem 1:

Continue the skip counting pattern for the next three numbers: 210,220,230,…210, 220, 230, \dots

Solution:

Step 1: Find the skip value by subtracting the first number from the second: 220−210=10220 - 210 = 10. \nStep 2: Add 1010 to the last known number: 230+10=240230 + 10 = 240. \nStep 3: Add 1010 to 240240: 240+10=250240 + 10 = 250. \nStep 4: Add 1010 to 250250: 250+10=260250 + 10 = 260. \nFinal Sequence: 210,220,230,240,250,260210, 220, 230, 240, 250, 260.

Explanation:

Since the difference between consecutive numbers is 1010, we are skip counting forward by tens.

Problem 2:

Fill in the missing number in the backward skip counting sequence: 550,500,…,400,350550, 500, \dots, 400, 350.

Solution:

Step 1: Find the skip value using the first two numbers: 550−500=50550 - 500 = 50. \nStep 2: Since the numbers are decreasing, subtract 5050 from the number before the gap: 500−50=450500 - 50 = 450. \nStep 3: Verify by subtracting 5050 from the result: 450−50=400450 - 50 = 400. This matches the next number in the sequence. \nMissing Number: 450450.

Explanation:

The sequence is decreasing by 5050 at each step, representing a backward skip count of 5050s.