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Can We Share? - Relationship between Multiplication and Division

Grade 3CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Equal Sharing: Division is the process of sharing a total number of items equally among a specific number of groups. For example, if you have 12 chocolates and 3 boxes, you place one chocolate in each box repeatedly until all are gone. You will see 4 chocolates in each box, which means 12÷3=412 \div 3 = 4.

Equal Grouping: This involves finding how many groups can be formed from a total when we know how many items go into each group. Imagine 15 buttons. If you put 5 buttons on each shirt, you can visualize 3 shirts being covered. This is written as 15÷5=315 \div 5 = 3.

Division as Repeated Subtraction: Division can be understood as subtracting the same number over and over until you reach zero. To solve 20÷520 \div 5, you subtract 5 from 20 (205=1520 - 5 = 15, 155=1015 - 5 = 10, 105=510 - 5 = 5, 55=05 - 5 = 0). Since you subtracted 5 four times, the answer is 4.

The Inverse Relationship: Multiplication and division are opposite operations. If you know that 4×6=244 \times 6 = 24, you automatically know two division facts: 24÷4=624 \div 4 = 6 and 24÷6=424 \div 6 = 4. You can visualize this as a Fact Family Triangle with 24 at the top and 4 and 6 at the bottom corners.

Parts of a Division Sentence: In the equation 18÷2=918 \div 2 = 9, 18 is the 'Dividend' (the total amount), 2 is the 'Divisor' (the number of groups or items per group), and 9 is the 'Quotient' (the result).

Division by 1 and Itself: When any number is divided by 1, the quotient is the number itself (8÷1=88 \div 1 = 8). When a number is divided by itself, the quotient is always 1 (8÷8=18 \div 8 = 1). Imagine having 8 balls and 1 bag; the bag gets all 8. If you have 8 balls and 8 bags, each bag gets only 1.

The Role of Zero: Zero divided by any number is always zero (0÷5=00 \div 5 = 0). However, we cannot divide any number by zero because we cannot share items among 'zero' groups.

📐Formulae

Total÷Number of Groups=Items per GroupTotal \div Number \ of \ Groups = Items \ per \ Group

Total÷Items per Group=Number of GroupsTotal \div Items \ per \ Group = Number \ of \ Groups

Dividend÷Divisor=QuotientDividend \div Divisor = Quotient

Divisor×Quotient=DividendDivisor \times Quotient = Dividend

a÷a=1a \div a = 1 (where a0a \neq 0)

a÷1=aa \div 1 = a

💡Examples

Problem 1:

Rohan has 28 marbles. He wants to put 7 marbles in each bag. How many bags does he need?

Solution:

Total number of marbles = 2828 Number of marbles per bag = 77 Number of bags needed = 28÷728 \div 7 We can use the multiplication table of 7: 7×1=77 \times 1 = 7, 7×2=147 \times 2 = 14, 7×3=217 \times 3 = 21, 7×4=287 \times 4 = 28. Since 7×4=287 \times 4 = 28, then 28÷7=428 \div 7 = 4.

Explanation:

This is an equal grouping problem. We divide the total amount by the number of items in each group to find the number of groups.

Problem 2:

Given the multiplication fact 9×3=279 \times 3 = 27, write two related division facts.

Solution:

The multiplication fact is 9×3=279 \times 3 = 27. Fact 1: 27÷9=327 \div 9 = 3 Fact 2: 27÷3=927 \div 3 = 9

Explanation:

Because multiplication and division are inverse operations, the product of the multiplication (2727) becomes the dividend in the division facts, and the two factors (99 and 33) swap roles as divisor and quotient.