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Algebra - Indices and Surds

Grade 12IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

๐Ÿ”‘Concepts

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Laws of Indices: Rules governing the manipulation of powers with the same base.

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Fractional Indices: Expressing roots as powers (e.g., square root as power of 1/2).

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Negative Indices: Expressing reciprocals using negative exponents.

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Simplifying Surds: Factoring out the largest perfect square from under the radical.

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Rationalizing the Denominator: Removing surds from the bottom of a fraction using conjugates.

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Exponential Equations: Solving for an unknown variable located in the exponent by equating bases.

๐Ÿ“Formulae

amร—an=am+na^m \times a^n = a^{m+n}

amรทan=amโˆ’na^m \div a^n = a^{m-n}

(am)n=amn(a^m)^n = a^{mn}

a0=1,(aโ‰ 0)a^0 = 1, (a \neq 0)

aโˆ’n=1ana^{-n} = \frac{1}{a^n}

a1n=ana^{\frac{1}{n}} = \sqrt[n]{a}

amn=(an)ma^{\frac{m}{n}} = (\sqrt[n]{a})^m

ab=aร—b\sqrt{ab} = \sqrt{a} \times \sqrt{b}

1a+b=1a+bร—aโˆ’baโˆ’b\frac{1}{a + \sqrt{b}} = \frac{1}{a + \sqrt{b}} \times \frac{a - \sqrt{b}}{a - \sqrt{b}}

๐Ÿ’กExamples

Problem 1:

Simplify the expression: (8x6)13ร—2xโˆ’2(8x^6)^{\frac{1}{3}} \times 2x^{-2}

Solution:

44

Explanation:

First, apply the power to the terms inside the bracket: 81/3ร—(x6)1/3=2ร—x28^{1/3} \times (x^6)^{1/3} = 2 \times x^2. Then multiply by the second term: 2x2ร—2xโˆ’2=4x2โˆ’2=4x02x^2 \times 2x^{-2} = 4x^{2-2} = 4x^0. Since x0=1x^0 = 1, the final answer is 4.

Problem 2:

Simplify 75โˆ’12\sqrt{75} - \sqrt{12} and express in the form k3k\sqrt{3}.

Solution:

333\sqrt{3}

Explanation:

Find the largest square factors: 75=25ร—3=53\sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3}. Also, 12=4ร—3=23\sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3}. Subtracting them gives 53โˆ’23=335\sqrt{3} - 2\sqrt{3} = 3\sqrt{3}.

Problem 3:

Rationalize the denominator: 43โˆ’5\frac{4}{3 - \sqrt{5}}

Solution:

3+53 + \sqrt{5}

Explanation:

Multiply the numerator and denominator by the conjugate (3+5)(3 + \sqrt{5}). Numerator: 4(3+5)=12+454(3 + \sqrt{5}) = 12 + 4\sqrt{5}. Denominator: (3โˆ’5)(3+5)=32โˆ’(5)2=9โˆ’5=4(3 - \sqrt{5})(3 + \sqrt{5}) = 3^2 - (\sqrt{5})^2 = 9 - 5 = 4. Dividing numerator by denominator: (12+45)/4=3+5(12 + 4\sqrt{5}) / 4 = 3 + \sqrt{5}.

Problem 4:

Solve for xx: 9xโˆ’1=27x+29^{x-1} = 27^{x+2}

Solution:

x=โˆ’8x = -8

Explanation:

Express both sides with base 3: (32)xโˆ’1=(33)x+2(3^2)^{x-1} = (3^3)^{x+2}. This simplifies to 32xโˆ’2=33x+63^{2x-2} = 3^{3x+6}. Equate the exponents: 2xโˆ’2=3x+62x - 2 = 3x + 6. Solving for xx gives x=โˆ’8x = -8.