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Application of Calculus - Marginal Cost and Marginal Revenue

Grade 12ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Total Cost Function C(x)C(x): This represents the total cost incurred in producing xx units of a commodity. It consists of two parts: Fixed Cost (FC), which is constant regardless of production levels, and Variable Cost (VC), which changes with the quantity produced. Visually, the Total Cost curve typically starts at a positive value on the vertical axis (the fixed cost) and slopes upward as xx increases.

Marginal Cost MCMC: This is the instantaneous rate of change of the total cost with respect to the number of units produced. Mathematically, it is the derivative of the cost function, MC=dCdxMC = \frac{dC}{dx}. Visually, at any production level xx, the marginal cost is represented by the slope of the tangent to the total cost curve at that point.

Average Cost ACAC: This is the cost per unit of production, calculated as AC=C(x)xAC = \frac{C(x)}{x}. Visually, the average cost at any point on the cost curve is the slope of the line segment connecting the origin to that point. The ACAC curve is typically U-shaped, indicating that unit costs decrease due to economies of scale before eventually rising.

Relationship between MCMC and ACAC: The Marginal Cost curve and Average Cost curve have a specific geometric relationship. When MC<ACMC < AC, the average cost is decreasing. When MC>ACMC > AC, the average cost is increasing. Consequently, the MCMC curve intersects the ACAC curve exactly at the minimum point of the ACAC curve.

Total Revenue R(x)R(x): This is the total amount received from selling xx units at a price pp per unit, given by R(x)=pxR(x) = p \cdot x. If the price is constant, the revenue curve is a straight line passing through the origin. If the price depends on demand (where p=f(x)p = f(x)), the curve is often a downward-opening parabola.

Marginal Revenue MRMR: This is the rate of change of total revenue with respect to the quantity sold, calculated as MR=dRdxMR = \frac{dR}{dx}. Visually, MRMR is the slope of the tangent to the total revenue curve. In a competitive market where price is constant, the MRMR curve is a horizontal line equal to the price pp.

Profit Function P(x)P(x): Profit is the difference between total revenue and total cost, P(x)=R(x)C(x)P(x) = R(x) - C(x). The break-even points occur where R(x)=C(x)R(x) = C(x), which are the points where the revenue and cost curves intersect on a graph, resulting in zero profit.

Marginal Average Cost MACMAC: This measures the rate of change of the average cost with respect to the output xx. It is found by differentiating the average cost function: MAC=ddx(AC)MAC = \frac{d}{dx}(AC). If MACMAC is negative, it indicates that the cost per unit is falling as production increases.

📐Formulae

C(x)=Fixed Cost+Variable CostC(x) = \text{Fixed Cost} + \text{Variable Cost}

AC=C(x)xAC = \frac{C(x)}{x}

MC=dCdxMC = \frac{dC}{dx}

R(x)=p×xR(x) = p \times x

MR=dRdxMR = \frac{dR}{dx}

P(x)=R(x)C(x)P(x) = R(x) - C(x)

MAC=ddx(AC)=xC(x)C(x)x2MAC = \frac{d}{dx}(AC) = \frac{x \cdot C'(x) - C(x)}{x^2}

Profit is maximized when MR=MC and d2Pdx2<0\text{Profit is maximized when } MR = MC \text{ and } \frac{d^2P}{dx^2} < 0

💡Examples

Problem 1:

The total cost function for a manufacturer is given by C(x)=110x2+5x+200C(x) = \frac{1}{10}x^2 + 5x + 200. Find the Marginal Cost and the Average Cost when 10 units are produced.

Solution:

Step 1: Find the Marginal Cost (MCMC) by differentiating C(x)C(x). MC=ddx(110x2+5x+200)=210x+5=0.2x+5MC = \frac{d}{dx}\left(\frac{1}{10}x^2 + 5x + 200\right) = \frac{2}{10}x + 5 = 0.2x + 5 Step 2: Substitute x=10x = 10 into the MCMC formula. MC(10)=0.2(10)+5=2+5=7MC(10) = 0.2(10) + 5 = 2 + 5 = 7 Step 3: Find the Average Cost (ACAC) formula. AC=C(x)x=110x2+5x+200x=0.1x+5+200xAC = \frac{C(x)}{x} = \frac{\frac{1}{10}x^2 + 5x + 200}{x} = 0.1x + 5 + \frac{200}{x} Step 4: Substitute x=10x = 10 into the ACAC formula. AC(10)=0.1(10)+5+20010=1+5+20=26AC(10) = 0.1(10) + 5 + \frac{200}{10} = 1 + 5 + 20 = 26 Therefore, at x=10x=10, Marginal Cost is 7 and Average Cost is 26.

Explanation:

We first apply the power rule of differentiation to find the rate of change of cost (Marginal Cost). Then, we divide the total cost by the quantity to find the cost per unit (Average Cost) before substituting the specific value of xx.

Problem 2:

The demand function for a product is p=40xp = 40 - x and the cost function is C(x)=x2+10xC(x) = x^2 + 10x. Find the Marginal Revenue when x=5x = 5.

Solution:

Step 1: Determine the Total Revenue function R(x)R(x). R(x)=px=(40x)x=40xx2R(x) = p \cdot x = (40 - x)x = 40x - x^2 Step 2: Find the Marginal Revenue (MRMR) by differentiating R(x)R(x). MR=dRdx=ddx(40xx2)=402xMR = \frac{dR}{dx} = \frac{d}{dx}(40x - x^2) = 40 - 2x Step 3: Substitute x=5x = 5 into the MRMR formula. MR(5)=402(5)=4010=30MR(5) = 40 - 2(5) = 40 - 10 = 30 The Marginal Revenue when 5 units are sold is 30.

Explanation:

Since revenue depends on both price and quantity, we first create the revenue function by multiplying the demand (price) by xx. We then differentiate this function to find the marginal revenue, which tells us the additional income generated by selling one more unit at that specific production level.